Question

我有一个包含三个独立变量的线性模型。我有下面的最终模型。我想使用increase_po和decrease_po变量来重新估计回归模型中的y值。

Dependent  Variable    Estimate    increase_po   decrease_po
Rate       Rate_lag1   0.54        0.60          0.49
Rate       UN          0.07        0.08          0.06
Rate       SQ          0.03        0.03          0.02

我想要做的是写一个do循环来产生六种可能性组合：

comb1  comb2   comb3  comb4   comb5  comb6
0.60   0.49    0.08   0.06    0.03   0.02
0.07   0.07    0.54   0.54    0.54   0.54
0.03   0.03    0.03   0.03    0.07   0.07

我想使用这些参数中的每一个来重新拟合模型并获得估计的y值。

fitted y1= b0 + 0.60*Rate_lag1 + 0.07*UN + 0.03*SQ  (only Rate_lag1 change parameter)

fitted y2= b0 + 0.49*Rate_lag1 + 0.07*UN + 0.03*SQ  (only Rate_lag1 change parameter)

fitted y3= b0 + 0.54*Rate_lag1 + 0.08*UN + 0.03*SQ  (only UN change parameter)

....................

因此，如果不使用宏和循环，甚至是不可能的。

Answer 1

我看到了你的另一个帖子，但想在这里发帖。

如果我理解正确：您已经为数据拟合了3个模型，每个模型使用相同的三个独立变量/预测变量。您已显示与3个模型的每个预测变量对应的beta参数。您希望从3个原始模型开始创建6个新模型，并且一次只更改一个beta参数。

下面是一些我认为可以做你想做的SAS代码。

然而，您的3个原始模型中的beta估计值非常相似！所以我不知道这个练习可以用最好的＆＃34;来表达。模型。

祝你好运！

data have;
    infile cards;
    input Dependent $  Variable $   Estimate    increase_po   decrease_po;
    cards;
Rate       Rate_lag1   0.54        0.60          0.49
Rate       UN          0.07        0.08          0.06
Rate       SQ          0.03        0.03          0.02
;
run;

*** TRANSPOSE SO EACH PREDICTOR VARIABLE IS A COLUMN AND EACH MODEL IS A ROW ***;
*** NOTE: RATE_LAG1 CHANGES TO RATE_LAG IN THE TRANSPOSE ***;
proc transpose data=have out=have_transpose;
    id variable;
    var Estimate    increase_po   decrease_po;
run;

*** CREATE VARIABLE FOR MODEL NUMBERS 1-3 ***;
data have_transpose;
    set have_transpose;
    modelnum=_N_;
run;    

proc print data=have_transpose;
run;

*** PUT EACH COLUMN INTO A SEPARATE DATASET AND KEEP ORIGINAL MODEL NUMBER IN EACH DATASET ***;
data col1(keep=rate_lag modelnum rename=(modelnum=rate_lag_num)) 
        col2(keep=un modelnum rename=(modelnum=un_num)) 
        col3(keep=sq modelnum rename=(modelnum=sq_num)) 
    ;
    set have_transpose;
run;

*** USE SQL TO DO A MANY-TO-MANY MERGE FOR ALL THREE DATASETS ***;
*** THE CREATED DATASET WILL CONTAIN ALL POSSIBLE COMBINATIONS OF PARAMETER ESTIMATES FROM ALL MODELS ***;
*** IN THIS CASE THERE WILL BE 3x3x3 = 27 RECORDS ***;
proc sql;
    create table col123 as
    select *
    from col1, col2, col3
;
quit;

data almost;
    set col123;
    *** FOR EACH POSSIBLE COMBINATION, COUNT HOW MANY PARAMETERS ARE UNCHANGED FROM MODEL 1 ***;
    flag = (rate_lag_num=1) + (un_num=1) + (sq_num=1);
run;

proc print data=almost;
run;

*** WANT TO ONLY KEEP MODELS WHERE TWO PARAMETERS ARE UNCHANGED ESTIMATES (WHERE FLAG=2) ***;
data want;
    set almost;
    if flag=2;
    keep rate_lag un sq ;
run;

*** THIS DATASET CONTAINS 6 RECORDS ***;
proc print data=want;
run;


*** FROM HERE YOU CAN USE SQL TO DO A MANY-TO-MANY MERGE WITH YOUR 6 NEW MODELS AND DATASET WITH THE PREDICTOR VARIABLES ***;
*** AND THEN CREATE YOUR NEW ESTIMATES FOR EACH MODEL ***;
*** SOMETHING LIKE THIS BELOW ***;
/*

*** RENAME VARIABLES AND CREATE NEW MODEL NUMBER ***;
data betas;
    set want;
    new_model_num = _N_;
    rename  rate_lag=rate_lag_beta  un=un_beta  sq=sq_beta ;
run;

proc sql;
    create table all as
    select * 
    from betas, ORIGINAL_DATA;  *** CHANGE "ORIGINAL_DATA" TO YOUR DATA SET NAME ***;
run;

data new_model;
    set all;
    fitted = b0 + (Rate_lag_beta * Rate_lag1) + (un_beta * un) + (sq_beta * sq);
run;
*/

*** NOTE: IN YOUR EXAMPLE, YOU ASSUME THE SAME B0 FOR ALL MODELS
*** HOWEVER, YOUR THREE STARTER MODELS MAY HAVE DIFFERENT B0 ESTIMATES ***;
*** SO YOU WILL HAVE TO THINK ABOUT THE BEST WAY TO HANDLE THAT ***;

如何在SAS中使用不同参数拟合线性回归模型

1 个答案: