我有下表：
ID GROUPID oDate oTime Value
1 A 2014-06-01 00:00:00 100
2 A 2014-06-01 01:00:00 200
3 A 2014-06-01 02:00:00 300
4 A 2014-06-01 03:00:00 400
5 A 2014-06-01 04:00:00 0
6 A 2014-06-01 05:00:00 10
7 A 2014-06-01 06:00:00 20
我希望得到以下结果：
A B C D E F
----------------------------------------------------------------------
1 ID GROUPID oDate oTime Value Result
2 1 A 2014-06-01 00:00:00 100
3 2 A 2014-06-01 01:00:00 200 100
4 3 A 2014-06-01 02:00:00 300 100
5 4 A 2014-06-01 03:00:00 400 100
6 5 A 2014-06-01 04:00:00 0 55
7 6 A 2014-06-01 05:00:00 10 10
8 7 A 2014-06-01 06:00:00 20 10
Result公式为（以excel格式）：
我将公式放在单元格F3上 - ＆gt; =IF(E3=0, IF(E4=0, 0, (F2+F4)/2), (E3-E2)
如何在SQL语法中执行此操作？有谁知道如何解决这个问题？ 谢谢。
答案 0 :(得分：2)
你可以写成：
;with CTE as
(
select T1.ID,
T1.GROUPID,
T1.oDate,
T1.oTime,
T1.Value,
--T2.oTime as previousrow,
--T3.oTime as nextrow,
case when T1.Value = 0 then 0 --E3=0
else T1.Value - T2.Value --(E3-E2)
end as Result
From test T1
left join test T2 on T1.oDate = T2.oDate and T1.GROUPID = T2.GROUPID
and DATEADD(Hour, -1, T1.oTime)= T2.oTime
left join test T3 on T1.oDate = T3.oDate and T1.GROUPID = T3.GROUPID
and DATEADD(Hour, 1, T1.oTime)= T3.oTime
)
,CTE2 as
( select
T1.ID,
T1.GROUPID,
T1.oDate,
T1.oTime,
T1.Value,
case when T1.Value = 0 then (T2.Result + T3.Result)/2
--(F2+F4)/2)
else T1.Result
end as Result
From CTE T1
left join CTE T2 on T1.oDate = T2.oDate and T1.GROUPID = T2.GROUPID
and DATEADD(Hour, -1, T1.oTime)= T2.oTime
left join CTE T3 on T1.oDate = T3.oDate and T1.GROUPID = T3.GROUPID
and DATEADD(Hour, 1, T1.oTime)= T3.oTime
)
select ID,
GROUPID,
oDate,
oTime,
Value,
Result
from CTE2
答案 1 :(得分：0)
我想我得到了你！测试这个
SELECT DISTINCT A.*,
CASE
WHEN A.VALUE = 0 THEN ( B.RESULT + C.RESULT ) / 2
ELSE A.RESULT
END AS RESULT
FROM (SELECT A.*,
A.VALUE - B.VALUE AS RESULT
FROM #TEMP1 A
JOIN #TEMP1 B
ON A.ID = ( B.ID + 1 )
AND A.GROUPID = B.GROUPID) A
LEFT JOIN (SELECT A.*,
A.VALUE - B.VALUE AS RESULT
FROM #TEMP1 A
JOIN #TEMP1 B
ON A.ID = ( B.ID + 1 )
AND A.GROUPID = B.GROUPID)B
ON A.ID = ( B.ID + 1 )
AND A.GROUPID = B.GROUPID
LEFT JOIN (SELECT A.*,
A.VALUE - B.VALUE AS RESULT
FROM #TEMP1 A
JOIN #TEMP1 B
ON A.ID = ( B.ID + 1 )
AND A.GROUPID = B.GROUPID)C
ON A.ID = ( C.ID - 1 )
AND A.GROUPID = C.GROUPID
答案 2 :(得分：0)
示例
create table YourTableName
(
ID int ,GROUPID varchar(2), oDate date, oTime time, Value int
)
insert YourTableName
(ID, GROUPID, oDate, oTime, Value)
values
(1, 'A', '2014-06-01', '00:00:00', 100),
(2, 'A', '2014-06-01', '01:00:00', 200),
(3, 'A', '2014-06-01', '02:00:00', 300),
(4, 'A', '2014-06-01', '03:00:00', 400),
(5, 'A', '2014-06-01', '04:00:00', 0),
(6, 'A', '2014-06-01', '05:00:00', 10),
(7, 'A', '2014-06-01', '06:00:00', 20);
go
create view vw_yourTableName
as
with cte_main
as (
select
ytn.ID,
ytn.GROUPID,
ytn.oDate,
ytn.oTime,
ytn.Value,
row_number() over (partition by ytn.GROUPID order by ytn.oDate, ytn.oTime) cte_rn
from
YourTableName as ytn
)
select
cte_main.ID,
cte_main.GROUPID,
cte_main.oDate,
cte_main.oTime,
cte_main.Value,
cte_lag.Value as Result
from
cte_main
left join cte_main as cte_lag
on cte_lag.cte_rn = cte_main.cte_rn - 1
go
select * from vw_yourTableName as vytn
drop table YourTableName
<强>结果
ID GROUPID oDate oTime Value Result
1 A 2014-06-01 00:00:00.0000000 100 NULL
2 A 2014-06-01 01:00:00.0000000 200 100
3 A 2014-06-01 02:00:00.0000000 300 200
4 A 2014-06-01 03:00:00.0000000 400 300
5 A 2014-06-01 04:00:00.0000000 0 400
6 A 2014-06-01 05:00:00.0000000 10 0
7 A 2014-06-01 06:00:00.0000000 20 10
答案 3 :(得分：0)
create table #temp1
(
ID int ,GROUPID varchar(2), oDate date, oTime time, Value int
)
insert #temp1
(ID, GROUPID, oDate, oTime, Value)
values
(1, 'A', '2014-06-01', '00:00:00', 100),
(2, 'A', '2014-06-01', '01:00:00', 200),
(3, 'A', '2014-06-01', '02:00:00', 300),
(4, 'A', '2014-06-01', '03:00:00', 400),
(5, 'A', '2014-06-01', '04:00:00', 0),
(6, 'A', '2014-06-01', '05:00:00', 10),
(7, 'A', '2014-06-01', '06:00:00', 20);
SELECT t.id,
t.value,
t.oDate,
t.oTime,
t.value - f.value result,
t.groupid
INTO #temp2
FROM #temp1 t
LEFT JOIN #temp1 f
ON t.id = f.id + 1 and t.groupid = f.groupid
SELECT id,
value,
oDate,
oTime,
groupid,
CASE
WHEN value <> 0 THEN result
ELSE ( (SELECT result
FROM #temp2
WHERE id = a.id - 1 and groupid = a.groupid)
+ (SELECT result
FROM #temp2
WHERE id = a.id + 1 and groupid = a.groupid) ) / 2
END result
FROM #temp2 a
OR
SELECT id,
value,
oDate,
oTime,
groupid,
CASE
WHEN value <> 0 THEN result
ELSE ( (SELECT result
FROM (SELECT t.id,
t.value,
t.oDate,
t.oTime,
t.value - f.value result,
t.groupid
FROM #temp1 t
LEFT JOIN #temp1 f
ON t.id = f.id + 1
AND t.groupid = f.groupid) b
WHERE b.id = a.id - 1
AND b.groupid = a.groupid)
+ (SELECT result
FROM (SELECT t.id,
t.value,
t.oDate,
t.oTime,
t.value - f.value result,
t.groupid
FROM #temp1 t
LEFT JOIN #temp1 f
ON t.id = f.id + 1
AND t.groupid = f.groupid) c
WHERE c.id = a.id + 1
AND c.groupid = a.groupid) ) / 2
END result
FROM (SELECT t.id,
t.value,
t.oDate,
t.oTime,
t.value - f.value result,
t.groupid
FROM #temp1 t
LEFT JOIN #temp1 f
ON t.id = f.id + 1
AND t.groupid = f.groupid) a