读下一条记录“NOT”以前的记录sql

Question

我有以下t-sql：

declare @startno int = 1, @finishno int = 365, @AfterO float = 97
declare @daysbet int = 80, @decVal float = 0.10 / 100;

;with ctetest as
(
select    @startno as oDay, 1 as oBet, @AfterO as Prod
    union all
    select     oDay +1, case when ((oBet + 1) = @daysbet) then 0 else (oBet + 1) end,
    case when (Prod = 0) then @AfterO else
         case when oBet = 0 then 0 else (Prod - (@decVal * Prod)) end
    end
    from ctetest
    where oDay+1 <= @finishno
    )
    select * from ctetest option (maxrecursion 0)

结果是：

----------------------------
oDay        oBet      Prod
----------------------------
1           1         97
2           2         96.903
3           3         96.806
ff.----->
80          0         89.628
81          1         0
82          2         97
ff.----->
364         44        93.008
365         45        92.915

但我想要的结果不是那样的，结果应该是这样的：

oDay        oBet      Prod
----------------------------
1           1         97
2           2         96.903
3           3         96.806
ff.----->
80          0         0
81          1         97
82          2         96.903
ff.----->
364         44        92.9
365         45        92.8

从上面的公式中，似乎case when oBet = 0读取了oBet列中的上一条记录。我想阅读Prod列中oBet列旁边的值。

请指教。谢谢。

Answer 1

更改

case when oBet = 0 then 0 else (Prod - (@decVal * Prod)) end

到

case when ((oBet + 1) = @daysbet) then 0 else (Prod - (@decVal * Prod)) end

因为oBet在下一次迭代中实际上变为0（在oDay = 81）