Question

使用argparse我得到了这个奇怪的ValueError for help选项。所有其他选项工作正常。只有帮助选项不起作用，这很奇怪。

以下是错误消息：

chaudhary@localhost:~/code/python/logmein$ ./logmein.py --bla
Usage:  ./logmein.py  [filename <Default: .login.txt>] || [password] || [username password]
chaudhary@localhost:~/code/python/logmein$ ./logmein.py --boo
Usage:  ./logmein.py  [filename <Default: .login.txt>] || [password] || [username password]
chaudhary@localhost:~/code/python/logmein$ ./logmein.py -b
Usage:  ./logmein.py  [filename <Default: .login.txt>] || [password] || [username password]
chaudhary@localhost:~/code/python/logmein$ ./logmein.py -h
Unexpected Error: <class 'ValueError'>
Details: unsupported format character 'p' (0x70) at index 1
Traceback (most recent call last):
  File "./logmein.py", line 222, in <module>
    main(sys.argv)
  File "./logmein.py", line 158, in main
    args, otherthings = parser.parse_known_args()
  File "/usr/lib64/python3.3/argparse.py", line 1737, in parse_known_args
    namespace, args = self._parse_known_args(args, namespace)
  File "/usr/lib64/python3.3/argparse.py", line 1943, in _parse_known_args
    start_index = consume_optional(start_index)
  File "/usr/lib64/python3.3/argparse.py", line 1883, in consume_optional
    take_action(action, args, option_string)


 File "/usr/lib64/python3.3/argparse.py", line 1811, in take_action
    action(self, namespace, argument_values, option_string)
  File "/usr/lib64/python3.3/argparse.py", line 1015, in __call__
    parser.print_help()
  File "/usr/lib64/python3.3/argparse.py", line 2339, in print_help
    self._print_message(self.format_help(), file)
  File "/usr/lib64/python3.3/argparse.py", line 2323, in format_help
    return formatter.format_help()
  File "/usr/lib64/python3.3/argparse.py", line 276, in format_help
    help = self._root_section.format_help()
  File "/usr/lib64/python3.3/argparse.py", line 206, in format_help
    func(*args)
  File "/usr/lib64/python3.3/argparse.py", line 293, in _format_usage
    usage = usage % dict(prog=self._prog)
ValueError: unsupported format character 'p' (0x70) at index 1

这是我的代码

# Parse command line arguments
from argparse import ArgumentParser
usage = "%prog [-f credential_file]"
parser = ArgumentParser(usage=usage)
parser.add_argument("-f", "--file", type=str, dest="file",
                    help="Use the specified file")
parser.add_argument("-o", "--logout", action='store_true', dest="logout",
                    help="Logout")
#parser.add_argument('otherthings', nargs='*')
#args = parser.parse_args()
args, otherthings = parser.parse_known_args()
argc = len(otherthings)

if args.file != None:
    username, password = parse_file_for_credential(args.file)

现在我无法找出为什么会出现这个ValueError，而且也只能找到--help选项。

Answer 1

引用the documentation：

请注意，程序名称（无论是从sys.argv[0]还是从prog=参数确定）可用于帮助使用%(prog)s格式说明符的消息。

尝试usage = "%(prog)s [-f credential_file]"

Answer 2

问题在于，当argparse尝试插入您的usage字符串时，Python会看到以下字符序列：%p。由于p不是a valid conversion flag，因此Python会引发ValueError。

您可以在REPL自己生成此错误：

>>> "This is valid: %s" % "magic"
"This is valid: magic"

>>> "This will raise a ValueError: %p" % "magic"
ValueError: unsupported format character 'p' (0x70)

发生这种情况的原因是因为您使用的是%prog而不是正确的%(prog)s（请注意%s中密钥周围的括号）。如Rob建议的那样，将usage = "%prog [-f credential_file]"更改为usage = "%(prog)s [-f credential_file]"，一切都会正常运作。

为什么argparse使用这种格式化语法？

argparse通过命名的格式参数提供类似程序名称的元数据，以允许参数以任何顺序出现，并允许重复。位置参数不能重复使用，并且必须按照提供的顺序显示：

>>> "If I want another %s then I need to add another %s" % ("param", "placeholder")
"If I want another param then I need to add another placeholder"
# There is no way to change the order around to be
# "If I want another placeholder then I need to add another param"
# without changing the order of the parameters passed to `%`

虽然命名参数可以重复并以任何顺序使用：

>>> s = "Any order, %(two)s / %(one)s. Repeats %(one)s / %(two)s are possible"
>>> s % {"one": "first", "two": "last"}
"Any order, last / first. Repeats first / last are possible"

argparse：使用带有nargs的--help或-h选项时的ValueError

2 个答案:

为什么argparse使用这种格式化语法？