Question

我正在开发一个需要检查作业截止日期的应用程序。我想知道截止日期是否在下周内，如果是，则执行某项操作我能找到的大部分文档都在Objective-C中，我无法弄清楚如何在Swift中完成它。谢谢你的帮助!!

Answer 1

如果您想为==支持<，>，<=，>=或NSDate，则必须在某处声明：

public func ==(lhs: NSDate, rhs: NSDate) -> Bool {
    return lhs === rhs || lhs.compare(rhs) == .OrderedSame
}

public func <(lhs: NSDate, rhs: NSDate) -> Bool {
    return lhs.compare(rhs) == .OrderedAscending
}

extension NSDate: Comparable { }

Answer 2

我喜欢使用扩展来使代码更具可读性。以下是一些NSDate扩展，可以帮助您清理代码并使其易于理解。我把它放在sharedCode.swift文件中：

extension NSDate {

    func isGreaterThanDate(dateToCompare: NSDate) -> Bool {
        //Declare Variables
        var isGreater = false

        //Compare Values
        if self.compare(dateToCompare as Date) == ComparisonResult.orderedDescending {
            isGreater = true
        }

        //Return Result
        return isGreater
    }

    func isLessThanDate(dateToCompare: NSDate) -> Bool {
        //Declare Variables
        var isLess = false

        //Compare Values
        if self.compare(dateToCompare as Date) == ComparisonResult.orderedAscending {
            isLess = true
        }

        //Return Result
        return isLess
    }

    func equalToDate(dateToCompare: NSDate) -> Bool {
        //Declare Variables
        var isEqualTo = false

        //Compare Values
        if self.compare(dateToCompare as Date) == ComparisonResult.orderedSame {
            isEqualTo = true
        }

        //Return Result
        return isEqualTo
    }

    func addDays(daysToAdd: Int) -> NSDate {
        let secondsInDays: TimeInterval = Double(daysToAdd) * 60 * 60 * 24
        let dateWithDaysAdded: NSDate = self.addingTimeInterval(secondsInDays)

        //Return Result
        return dateWithDaysAdded
    }

    func addHours(hoursToAdd: Int) -> NSDate {
        let secondsInHours: TimeInterval = Double(hoursToAdd) * 60 * 60
        let dateWithHoursAdded: NSDate = self.addingTimeInterval(secondsInHours)

        //Return Result
        return dateWithHoursAdded
    }
}

现在，如果你能做到这样的事情：

//Get Current Date/Time
var currentDateTime = NSDate()

//Get Reminder Date (which is Due date minus 7 days lets say)
var reminderDate = dueDate.addDays(-7)

//Check if reminderDate is Greater than Right now
if(reminderDate.isGreaterThanDate(currentDateTime)) {
    //Do Something...
}

Answer 3

这是你在Swift中比较两个NSDates的方法，我刚在Xcode的游乐场测试过它：

if date1.compare(date2) == NSComparisonResult.OrderedDescending
{
    NSLog("date1 after date2");
} else if date1.compare(date2) == NSComparisonResult.OrderedAscending
{
    NSLog("date1 before date2");
} else
{
    NSLog("dates are equal");
}

所以要检查日期dueDate是否在一周之内：

let dueDate=...

let calendar = NSCalendar.currentCalendar()
let comps = NSDateComponents()
comps.day = 7
let date2 = calendar.dateByAddingComponents(comps, toDate: NSDate(), options: NSCalendarOptions.allZeros)

if dueDate.compare(date2!) == NSComparisonResult.OrderedDescending
{
    NSLog("not due within a week");
} else if dueDate.compare(date2!) == NSComparisonResult.OrderedAscending
{
    NSLog("due within a week");
} else
{
    NSLog("due in exactly a week (to the second, this will rarely happen in practice)");
}

Answer 4

我总是在一行中做到这一点：

let greater = date1.timeIntervalSince1970 < date2.timeIntervalSince1970

在if块

中仍然可读

Answer 5

在Swift3中，Date中的Foundation结构现在实现了Comparable协议。因此，之前的Swift2 NSDate方法被Swift3 Date取代。

/**
 `Date` represents a single point in time.

 A `Date` is independent of a particular calendar or time zone. To represent a `Date` to a user, you must interpret it in the context of a `Calendar`.
*/
public struct Date : ReferenceConvertible, Comparable, Equatable {

    // .... more         

    /**
        Returns the interval between the receiver and another given date.

        - Parameter another: The date with which to compare the receiver.

        - Returns: The interval between the receiver and the `another` parameter. If the receiver is earlier than `anotherDate`, the return value is negative. If `anotherDate` is `nil`, the results are undefined.

        - SeeAlso: `timeIntervalSince1970`
        - SeeAlso: `timeIntervalSinceNow`
        - SeeAlso: `timeIntervalSinceReferenceDate`
        */
    public func timeIntervalSince(_ date: Date) -> TimeInterval

   // .... more 

    /// Returns true if the two `Date` values represent the same point in time.
    public static func ==(lhs: Date, rhs: Date) -> Bool

    /// Returns true if the left hand `Date` is earlier in time than the right hand `Date`.
    public static func <(lhs: Date, rhs: Date) -> Bool

    /// Returns true if the left hand `Date` is later in time than the right hand `Date`.
    public static func >(lhs: Date, rhs: Date) -> Bool

    /// Returns a `Date` with a specified amount of time added to it.
    public static func +(lhs: Date, rhs: TimeInterval) -> Date

    /// Returns a `Date` with a specified amount of time subtracted from it.
    public static func -(lhs: Date, rhs: TimeInterval) -> Date

  // .... more
}

注意......

在Swift3中，Date为struct，表示它为value type。 NSDate为class，为reference type。

// Swift3
let a = Date()
let b = a //< `b` will copy `a`. 

// So, the addresses between `a` and `b` are different.
// `Date` is some kind different with `NSDate`.

Answer 6

extension NSDate {

    // MARK: - Dates comparison

    func isGreaterThanDate(dateToCompare: NSDate) -> Bool {

        return self.compare(dateToCompare) == NSComparisonResult.OrderedDescending
    }

    func isLessThanDate(dateToCompare: NSDate) -> Bool {

        return self.compare(dateToCompare) == NSComparisonResult.OrderedAscending
    }

    func equalToDate(dateToCompare: NSDate) -> Bool {

        return self.compare(dateToCompare) == NSComparisonResult.OrderedSame
    }
}

Answer 7

如果您想在swift 3上比较日期与粒度（同一天或同一天等）。

func compareDate(date1:NSDate, date2:NSDate, toUnitGranularity: NSCalendar.Unit) -> Bool {

 let order = NSCalendar.current.compare(date1 as Date, to: date2 as Date, toGranularity: .day)
 switch order {
 case .orderedSame:
   return true
 default:
   return false
 }
}

对于其他日历比较，将.day更改为;

.year 。月。天。小时。分钟。第二

Answer 8

Swift已经实现日期比较，只需使用date1＆gt; date2等等。

/// Returns true if the two `Date` values represent the same point in time.
public static func ==(lhs: Date, rhs: Date) -> Bool

/// Returns true if the left hand `Date` is earlier in time than the right hand `Date`.
public static func <(lhs: Date, rhs: Date) -> Bool

/// Returns true if the left hand `Date` is later in time than the right hand `Date`.
public static func >(lhs: Date, rhs: Date) -> Bool

/// Returns a `Date` with a specified amount of time added to it.
public static func +(lhs: Date, rhs: TimeInterval) -> Date

/// Returns a `Date` with a specified amount of time subtracted from it.
public static func -(lhs: Date, rhs: TimeInterval) -> Date

/// Add a `TimeInterval` to a `Date`.
///
/// - warning: This only adjusts an absolute value. If you wish to add calendrical concepts like hours, days, months then you must use a `Calendar`. That will take into account complexities like daylight saving time, months with different numbers of days, and more.
public static func +=(lhs: inout Date, rhs: TimeInterval)

/// Subtract a `TimeInterval` from a `Date`.
///
/// - warning: This only adjusts an absolute value. If you wish to add calendrical concepts like hours, days, months then you must use a `Calendar`. That will take into account complexities like daylight saving time, months with different numbers of days, and more.
public static func -=(lhs: inout Date, rhs: TimeInterval)

Answer 9

在Swift 3中，日期是可比较的，所以我们可以直接比较日期，如

let date1 = Date()
let date2 = Date()

let isGreater = date1 > date2
print(isGreater)

let isEqual = date1 == date2
print(isEqual)

或者

let result = date1.compare(date2)
switch result {
    case .OrderedAscending     :   print("date 1 is earlier than date 2")
    case .OrderedDescending    :   print("date 1 is later than date 2")
    case .OrderedSame          :   print("two dates are the same")
}

更好地在日期

上创建extension

extension Date {

  fun isGreater(than date: Date) -> Bool {
    return self > date 
  }

  func isSmaller(than date: Date) -> Bool {
    return self < date
  }

  func isEqual(to date: Date) -> Bool {
    return self == date
  }

}

使用let isGreater = date1.isGreater(than: date2)

Answer 10

这个函数对我有用，可以比较一个日期（startDate）是否在endDate之后，两者都被定义为NSDate变量：

if startDate.compare(endDate as Date) == ComparisonResult.orderedDescending

Answer 11

Swift

中的实施

let documentsPath = NSSearchPathForDirectoriesInDomains(.DocumentDirectory, .UserDomainMask, true)[0] as NSString
let files = NSFileManager.defaultManager().contentsOfDirectoryAtPath(documentsPath, error: nil)

let filesAndProperties = NSMutableArray()
for file in files! {

    let filePath = documentsPath.stringByAppendingString(file as NSString)
    let properties = NSFileManager.defaultManager().attributesOfItemAtPath(filePath, error: nil)
    let modDate = properties![NSFileModificationDate] as NSDate
    filesAndProperties.addObject(NSDictionary(objectsAndKeys: file, "path", modDate, "lastModDate"))
}

let sortedFiles = filesAndProperties.sortedArrayUsingComparator({
    (path1, path2) -> NSComparisonResult in

    var comp = (path1.objectForKey("lastModDate") as NSDate).compare(path2.objectForKey("lastModDate") as NSDate)
    if comp == .OrderedDescending {

        comp = .OrderedAscending
    } else if comp == .OrderedAscending {

        comp = .OrderedDescending
    }

    return comp
})

Answer 12

var dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd"
let dateData: String = dateFormatter.stringFromDate(date1)
let testDate: String = dateFormatter.stringFromDate(date2)
print(dateData == testDate)

Answer 13

我们有办法检查当前时间是否两次（两个日期）。例如，我想检查诊所（医院）开放时间和关闭时间之间的当前谎言。

使用简单的代码。

      NSDate * now = [NSDate date];
        NSDateFormatter *outputFormatter = [[NSDateFormatter alloc] init];
        [outputFormatter setDateFormat:@"HH:mm:ss"];

        //current time
        NSString *currentTimeString = [outputFormatter stringFromDate:now];
        NSDate *dateCurrent = [outputFormatter dateFromString:currentTimeString];


        NSString *timeStart = @"09:00:00";
        NSString *timeEnd = @"22:00:00";

        NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
        [formatter setDateFormat:@"HH:mm:ss"];

        NSDate *dateStart= [formatter timeStart];
        NSDate *dateEnd = [formatter timeEnd];
        NSComparisonResult result = [dateCurrent compare:dateStart];
        NSComparisonResult resultSecond = [date2 compare:dateEnd];

if(result == NSOrderedDescending && resultSecond == NSOrderedDescending)
        {
            NSLog(@"current time lies in starting and end time");
    }else {
            NSLog(@"current time doesn't lie in starting and end time");
        }

Answer 14

对于swift 3，您可以使用以下功能在两个日期之间进行比较。

func compareDate(dateInitial:Date, dateFinal:Date) -> Bool {
    let order = Calendar.current.compare(dateInitial, to: dateFinal, toGranularity: .day)
    switch order {
    case .orderedSame:
        return true
    default:
        return false
    }
}

toGranularity可以根据您要应用比较的约束进行更改。

Answer 15

延伸SashaZ

Swift iOS 8及以上当您需要的不仅仅是更大或更小的日期比较时。例如，它是在同一天或前一天，......

注意：永远不要忘记时区。日历时区有默认值，但如果您不喜欢默认值，则必须自己设置时区。要知道它是哪一天，你需要知道你在问哪个时区。

extension Date {
    func compareTo(date: Date, toGranularity: Calendar.Component ) -> ComparisonResult  {
        var cal = Calendar.current
        cal.timeZone = TimeZone(identifier: "Europe/Paris")!
        return cal.compare(self, to: date, toGranularity: toGranularity)
        }
    }

像这样使用：

if thisDate.compareTo(date: Date(), toGranularity: .day) == .orderedDescending {
// thisDate is a previous day
}

一个更复杂的例子。查找并过滤数组中的所有日期，这些日期与“findThisDay”的日期相同：

let formatter = DateFormatter()
formatter.timeZone = TimeZone(identifier: "Europe/Paris")
formatter.dateFormat = "yyyy/MM/dd HH:mm:ss"

let findThisDay = formatter.date(from: "2018/11/05 08:11:08")!
_ = [
    formatter.date(from: "2018/12/05 08:08:08")!, 
    formatter.date(from: "2018/11/05 08:11:08")!,
    formatter.date(from: "2018/11/05 11:08:22")!,
    formatter.date(from: "2018/11/05 22:08:22")!,
    formatter.date(from: "2018/11/05 08:08:22")!,
    formatter.date(from: "2018/11/07 08:08:22")!,
    ]
    .filter{ findThisDay.compareTo(date: $0 , toGranularity: .day) == .orderedSame }
    .map { print(formatter.string(from: $0)) }

Answer 16

someArray.sort({($0.dateAdded?.timeIntervalSinceReferenceDate)! < ($1.dateAdded?.timeIntervalSinceReferenceDate)!})

dateAdded是我的对象中的NSDate变量

class MyClass {
    let dateAdded: NSDate?
}

使用Swift进行NSDate比较

16 个答案:

注意......