我正在使用try
中的ios应用程序,我有一个包含7个选项的滑块。每个选项代表特定日期。
到目前为止,我的代码如下:
swift
如上所示 - 我在控制台中打印出要返回的内容。
但是,我希望以func convertValueToDate(value: Float) -> NSDate{
var currentDate:NSDate = NSDate()
switch(value){
case 1:
print("5 years ago")
return NSDate()
case 2:
print("one year ago")
return NSDate()
case 3:
print("six months ago")
return NSDate()
case 4:
print("one month ago")
return NSDate()
case 5:
print("one week ago")
return NSDate()
case 6:
print("yesterday")
return NSDate()
case 7:
print("today")
return NSDate()
default:
print("default date")
return NSDate()
}
}
格式返回这些日期而不是打印。
我不知道如何计算每个选项的时间,因为我希望每天NSDate
小时。所以,例如。当用户输入数字0:00:01 AM
时,我想告诉他昨天7
的确切日期。当用户选择号码0:00:01 AM
时,我想在一周前给他一个时间5
的日期,依此类推。如何计算它,以便此函数始终返回时间0:00:01 AM
和计算日期?
答案 0 :(得分:1)
您可以使用NSCalendar方法dateByAddingUnit:
func convertValueToDate(value: Float) -> NSDate {
struct Cal {
static let iso8601 = NSCalendar(identifier: NSCalendarIdentifierISO8601)!
}
let now = NSDate()
print("now: ", now)
switch(value) {
case 1:
print("5 years ago")
return Cal.iso8601.dateByAddingUnit(.Year, value: -5, toDate: now, options: [])!
case 2:
print("one year ago")
return Cal.iso8601.dateByAddingUnit(.Year, value: -1, toDate: now, options: [])!
case 3:
print("six months ago")
return Cal.iso8601.dateByAddingUnit(.Month, value: -6, toDate: now, options: [])!
case 4:
print("one month ago")
return Cal.iso8601.dateByAddingUnit(.Month, value: -1, toDate: now, options: [])!
case 5:
print("one week ago")
return Cal.iso8601.dateByAddingUnit(.WeekOfYear, value: -1, toDate: now, options: [])!
case 6:
print("yesterday")
return Cal.iso8601.dateByAddingUnit(.Day, value: -1, toDate: now, options: [])!
case 7:
print("today")
return now
default:
print("default date")
return now
}
}
如果您需要返回该日期的当天开始,则可以使用NSCalendar startOfDayForDate方法。
func convertValueToDate(value: Float) -> NSDate {
struct Cal {
static let iso8601 = NSCalendar(identifier: NSCalendarIdentifierISO8601)!
}
let now = NSDate()
print("now: ", now)
let result: NSDate
switch(value) {
case 1:
print("5 years ago")
result = Cal.iso8601.dateByAddingUnit(.Year, value: -5, toDate: now, options: [])!
case 2:
print("one year ago")
result = Cal.iso8601.dateByAddingUnit(.Year, value: -1, toDate: now, options: [])!
case 3:
print("six months ago")
result = Cal.iso8601.dateByAddingUnit(.Month, value: -6, toDate: now, options: [])!
case 4:
print("one month ago")
result = Cal.iso8601.dateByAddingUnit(.Month, value: -1, toDate: now, options: [])!
case 5:
print("one week ago")
result = Cal.iso8601.dateByAddingUnit(.WeekOfYear, value: -1, toDate: now, options: [])!
case 6:
print("yesterday")
result = Cal.iso8601.dateByAddingUnit(.Day, value: -1, toDate: now, options: [])!
case 7:
print("today")
result = now
default:
print("default date")
result = now
}
return Cal.iso8601.startOfDayForDate(result)
}
答案 1 :(得分:0)
这里是Swift 3中的一个解决方案,因为它已经在这里了(对于Swift 2.x在类之前添加NS
前缀应该可以做到这一点):
import Foundation
func convertValueToDate(value: Float) -> Date{
let calendar = Calendar.current
let currentDate = calendar.date(bySettingHour: 00, minute: 00, second: 01, of: Date())!
func dateByAdding(_ value: Int, _ component: Calendar.Component) -> Date {
return calendar.date(byAdding: component, value: value, to: currentDate)!
}
switch(value){
case 1:
print("5 years ago")
return dateByAdding(-5, .year)
case 2:
print("one year ago")
return dateByAdding(-1, .year)
case 3:
print("six months ago")
return dateByAdding(-6, .month)
case 4:
print("one month ago")
return dateByAdding(-1, .month)
case 5:
print("one week ago")
return dateByAdding(-7, .day)
case 6:
print("yesterday")
return dateByAdding(-1, .day)
case 7:
print("today")
return currentDate
default:
print("default date")
return currentDate
}
}