我正在编写一个命令行工具,它将从文本文件中删除对等项。
这是文本文件。它在代码中的引用是cfg.Bootstrap
"Bootstrap": [
{
"Address": "/ip4/162.243.139.64/tcp/5001",
"PeerID": "QmXZPT1SLcczjNSLnSCsQBWwbosKjrDRo122Ys8ajKoQXQ"
},
{
"Address": "/ip4/162.243.139.64/tcp/5001",
"PeerID": "QmXZPT1SLcczjNSLnSCsQBWwbosKjrDRo122Ys8ajKoQXA"
},
{
"Address": "/ip4/162.243.139.64/tcp/5001",
"PeerID": "QmXZPT1SLcczjNSLnSCsQBWwbosKjrDRo122Ys8ajKoQXQ"
},
{
"Address": "/ip4/162.243.139.64/tcp/5001",
"PeerID": "QmXZPT1SLcczjNSLnSCsQBWwbosKjrDRo122Ys8ajKoQXA"
}
使用用户提供的PeerID和地址创建对等对象。看起来像这样
peer := config.BootstrapPeer{
Address: address,
PeerID: pID,
}
目标是删除包含用户提供的地址和PeerID的所有对等cfg.Bootstrap
//iterate through the list of peers multiple times so that we delete all matches
for i := range cfg.Bootstrap {
//iterate through the list of peers
for i, val := range cfg.Bootstrap {
//if the user supplied PeerID and Address match a Peer object in cfg.Bootstrap..
if(val.PeerID == peer.PeerID && val.Address == peer.Address) {
//remove that element
cfg.Bootstrap = append(cfg.Bootstrap[:i], cfg.Bootstrap[i+1:]...)
}
}
fmt.Println(i)
}
这适用于cfg.Bootstrap中的最后一个对等项有重复。如果它有重复,那么Go恐慌与
panic: runtime error: slice bounds out of range
我需要这样做,以便用户可以删除包含最后一个对等体的对等体的所有副本。有什么想法吗?
答案 0 :(得分:8)
基本思想是将值!=复制到切片的开头,并在完成时修剪多余的部分。
i := 0
for _, v := range cfg.Bootstrap {
if v.PeerId == peer.PeerId && v.Address == peer.Address {
continue
}
cfg.Bootstrap[i] = v
i++
}
cfg.Bootstrap = cfg.Bootstrap[:i]
答案 1 :(得分:0)
另一种方法(如果您有选择)是先排序,然后删除重复项。例如用字符串;
strs = []string{"a", "b", "c", "d", "e", "b", "a", "e", "e", "d"}
sort.Strings(strs)
var last string
first_item := true
dedupped := []string{}
for _, s := range strs {
if first_item {
dedupped = append(dedupped, s)
first_item = false
} else {
if s != last {
dedupped = append(dedupped, s)
}
}
last = s
}