所以我试图在HTML5画布中创建一个绘图工具,其中笔划的重量越大,移动鼠标的速度越快,移动速度越慢。我使用ctx.lineTo(),但是在我的第一次尝试中注意到,如果我移动得太快,厚度的变化会记录为明显的方形增量(而不是平滑增加的重量)
所以我将ctx.lineJoin和ctx.lineCap更改为" round"它有点好转
但这仍然不像我想的那么顺利。我正在为这样的事情拍摄
关于如何使体重变化更平滑的任何建议都会很棒!这是一个有效的演示:http://jsfiddle.net/0fhag522/1/
这里'预览我的" dot"对象(笔)和我的绘图功能:
var dot = {
start: false,
weight: 1,
open: function(x,y){
ctx.lineJoin = "round";
ctx.lineCap = "round";
ctx.beginPath();
ctx.moveTo(x,y);
},
connect: function(x,y){
ctx.lineWidth = this.weight;
ctx.lineTo(x,y);
ctx.stroke();
ctx.closePath();
ctx.beginPath();
ctx.moveTo(x,y);
},
close: function(){
ctx.closePath();
}
}
function draw(){
if(down){
if(!dot.start){
dot.close();
prevx = mx; prevy = my;
dot.open(mx,my);
dot.start=true;
}
else {
var dx = (prevx>mx) ? prevx-mx : mx-prevx;
var dy = (prevy>my) ? prevy-my : my-prevy;
dot.weight = Math.abs(dx-dy)/2;
dot.connect( mx,my );
prevx = mx; prevy = my;
}
}
}
答案 0 :(得分:0)
由于画布没有可变宽度线,因此必须在线点之间绘制闭合路径。
然而,这留下了明显的对接。
要平滑对接关节,可以在每个关节处画一个圆圈。
以下是示例代码和演示:
var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
var cw = canvas.width;
var ch = canvas.height;
var $canvas = $("#canvas");
var canvasOffset = $canvas.offset();
var offsetX = canvasOffset.left;
var offsetY = canvasOffset.top;
var scrollX = $canvas.scrollLeft();
var scrollY = $canvas.scrollTop();
var isDown = false;
var startX;
var startY;
var PI = Math.PI;
var halfPI = PI / 2;
var points = [];
$("#canvas").mousedown(function(e) {
handleMouseDown(e);
});
function handleMouseDown(e) {
e.preventDefault();
e.stopPropagation();
mx = parseInt(e.clientX - offsetX);
my = parseInt(e.clientY - offsetY);
var pointsLength = points.length;
if (pointsLength == 0) {
points.push({
x: mx,
y: my,
width: Math.random() * 5 + 2
});
} else {
var p0 = points[pointsLength - 1];
var p1 = {
x: mx,
y: my,
width: Math.random() * 5 + 2
};
addAngle(p0, p1);
p0.angle = p1.angle;
addEndcap(p0);
addEndcap(p1);
points.push(p1);
extendLine(p0, p1);
}
}
function addAngle(p0, p1) {
var dx = p1.x - p0.x;
var dy = p1.y - p0.y;
p1.angle = Math.atan2(dy, dx);
}
function addEndcap(p) {
p.x0 = p.x + p.width * Math.cos(p.angle - halfPI);
p.y0 = p.y + p.width * Math.sin(p.angle - halfPI);
p.x1 = p.x + p.width * Math.cos(p.angle + halfPI);
p.y1 = p.y + p.width * Math.sin(p.angle + halfPI);
}
function extendLine(p0, p1) {
ctx.beginPath();
ctx.moveTo(p0.x0, p0.y0);
ctx.lineTo(p0.x1, p0.y1);
ctx.lineTo(p1.x1, p1.y1);
ctx.lineTo(p1.x0, p1.y0);
ctx.closePath();
ctx.fillStyle = 'blue';
ctx.fill();
// draw a circle to cover the butt-joint
ctx.beginPath();
ctx.moveTo(p1.x, p1.y);
ctx.arc(p1.x, p1.y, p1.width, 0, Math.PI * 2);
ctx.closePath();
ctx.fill();
}
body{ background-color: ivory; }
#canvas{border:1px solid red;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<h4>Click to add line segments.</h4>
<canvas id="canvas" width=300 height=300></canvas>
答案 1 :(得分:0)
这是创建具有圆线上限的生长线的简单功能:
/*
* this function returns a Path2D object
* the path represents a growing line between two given points
*/
function createGrowingLine (x1, y1, x2, y2, startWidth, endWidth) {
// calculate direction vector of point 1 and 2
const directionVectorX = x2 - x1,
directionVectorY = y2 - y1;
// calculate angle of perpendicular vector
const perpendicularVectorAngle = Math.atan2(directionVectorY, directionVectorX) + Math.PI/2;
// construct shape
const path = new Path2D();
path.arc(x1, y1, startWidth/2, perpendicularVectorAngle, perpendicularVectorAngle + Math.PI);
path.arc(x2, y2, endWidth/2, perpendicularVectorAngle + Math.PI, perpendicularVectorAngle);
path.closePath();
return path;
}
const ctx = myCanvas.getContext('2d');
// create a growing line between P1(10, 10) and P2(250, 100)
// with a start line width of 10 and an end line width of 50
let line1 = createGrowingLine(10, 10, 250, 100, 10, 50);
ctx.fillStyle = 'green';
// draw growing line
ctx.fill(line1);
<canvas width="300" height="150" id="myCanvas"></canvas>
说明:
函数createGrowingLine
通过以下方式在两个给定点之间构造形状:
如果您不想使用圆角线帽,请使用以下功能:
/*
* this function returns a Path2D object
* the path represents a growing line between two given points
*/
function createGrowingLine (x1, y1, x2, y2, startWidth, endWidth) {
const startRadius = startWidth/2;
const endRadius = endWidth/2;
// calculate direction vector of point 1 and 2
let directionVectorX = x2 - x1,
directionVectorY = y2 - y1;
// calculate vector length
const directionVectorLength = Math.hypot(directionVectorX, directionVectorY);
// normalize direction vector (and therefore also the perpendicular vector)
directionVectorX = 1/directionVectorLength * directionVectorX;
directionVectorY = 1/directionVectorLength * directionVectorY;
// construct perpendicular vector
const perpendicularVectorX = -directionVectorY,
perpendicularVectorY = directionVectorX;
// construct shape
const path = new Path2D();
path.moveTo(x1 + perpendicularVectorX * startRadius, y1 + perpendicularVectorY * startRadius);
path.lineTo(x1 - perpendicularVectorX * startRadius, y1 - perpendicularVectorY * startRadius);
path.lineTo(x2 - perpendicularVectorX * endRadius, y2 - perpendicularVectorY * endRadius);
path.lineTo(x2 + perpendicularVectorX * endRadius, y2 + perpendicularVectorY * endRadius);
path.closePath();
return path;
}
const ctx = myCanvas.getContext('2d');
// create a growing line between P1(10, 10) and P2(250, 100)
// with a start line width of 10 and an end line width of 50
let line1 = createGrowingLine(10, 10, 250, 100, 10, 50);
ctx.fillStyle = 'green';
// draw growing line
ctx.fill(line1);
<canvas width="300" height="150" id="myCanvas"></canvas>