我目前拥有的是很多html元素,以及jQuery和css来创建一个基于鼠标移动效果的点阵图案。很难解释所以我做了一个例子。 http://jsfiddle.net/sebastianscholten/u6ebt390/
var mX, mY, distance;
function theDistance(elem, mouseX, mouseY) {
return Math.floor(Math.sqrt(Math.pow(mouseX - (elem.offset().left+(elem.width()/2)), 2) + Math.pow(mouseY - (elem.offset().top+(elem.height()/2)), 2)));
}
$(document).mousemove(function(e) {
mX = e.pageX;
mY = e.pageY;
cutoff = 100;
$('.element').each(function(){
distance = theDistance($(this), mX, mY);
if (distance <= cutoff) {
$(this).css('transform', 'scale(' + (distance*(1/cutoff)-1) + ')');
} else {
$(this).css('transform', 'scale(0)');
}
});
});
问题是性能有问题,所以我想用html画布制作相同的效果。我不知道它是否会起作用。
你们知道其他任何方式我可以在没有大量html元素的情况下创建相同的效果。感谢。
编辑:感谢markE的回答。这对我帮助很大。这就是我想出来的。
var c = document.getElementById("canvas");
var ctx = c.getContext("2d");
var circleRadius = 1;
var circleMargin = 10;
var canvasW = c.width;
var canvasH = c.height;
var $canvas = $("#canvas");
var canvasOffset = $canvas.offset();
var offsetX = canvasOffset.left;
var offsetY = canvasOffset.top;
var circleAmountX = canvasW / (circleRadius + (2 * circleMargin));
var circleAmountY = canvasH / (circleRadius + (2 * circleMargin));
function draw(mouseX, mouseY) {
ctx.clearRect(0, 0, canvasW, canvasH);
for (i = 0; i < circleAmountX + 1; i++) {
for (k = 0; k < circleAmountY + 1; k++) {
var x = i * (circleRadius + circleMargin * 2);
var y = k * (circleRadius + circleMargin * 2);
var dx = mouseX - x;
var dy = mouseY - y;
var inflation = 1;
var inflationAmount = 6;
var cutoff = 150;
var distance = Math.sqrt(dx * dx + dy * dy);
if (distance <= cutoff && distance > 0) {
inflation = inflationAmount - (distance / ((cutoff / inflationAmount) + 2));
} else if (distance = 0) {
inflation = inflationAmount;
}
ctx.beginPath();
ctx.arc(x, y, circleRadius * inflation, 0, 2 * Math.PI);
ctx.fill();
ctx.closePath();
}
}
}
draw(0, 0);
$("#canvas").mousemove(function (e) {
var mX = parseInt(e.clientX - offsetX);
var mY = parseInt(e.clientY - offsetY);
draw(mX, mY);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
<canvas id="canvas" width=500 height=500></canvas>
答案 0 :(得分:4)
是的,您可以使用画布获得更好的效果:
收听mousemove事件
计算鼠标与鼠标之间的距离。圆心:
var dx=mouseX-centerX;
var dy=mouseY-centerY;
var distance=Math.sqrt(dx*dx+dy*dy);
根据鼠标与圆圈的接近程度重绘一个膨胀/缩小的圆圈
祝你的项目好运!
这是一个带有1个圆圈的概念验证:
var canvas=document.getElementById("canvas");
var ctx=canvas.getContext("2d");
var $canvas=$("#canvas");
var canvasOffset=$canvas.offset();
var offsetX=canvasOffset.left;
var offsetY=canvasOffset.top;
var cx=150;
var cy=150;
var radius=30;
var inflation=.25;
draw();
$("#canvas").mousemove(function(e){handleMouseMove(e);});
function draw(){
ctx.clearRect(0,0,canvas.width,canvas.height);
ctx.beginPath();
ctx.arc(150,150,inflation,0,Math.PI*2);
ctx.closePath();
ctx.fill();
ctx.stroke();
}
function handleMouseMove(e){
e.preventDefault();
e.stopPropagation();
mouseX=parseInt(e.clientX-offsetX);
mouseY=parseInt(e.clientY-offsetY);
var dx=mouseX-cx;
var dy=mouseY-cy;
var distance=Math.sqrt(dx*dx+dy*dy);
if(distance<radius){
inflation=radius;
}else if(distance<50){
inflation=radius*.75;
}else if(distance<75){
inflation=radius*.50;
}else{
inflation=radius*.25;
}
draw();
}
body{ background-color: ivory; }
#canvas{border:1px solid red;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<h4>Approach the circle with the mouse</h4>
<canvas id="canvas" width=300 height=300></canvas>