我从Python脚本获得了一个奇怪的输出
当在循环中运行代码以实现涉及Paramiko的实际执行时,它似乎颠倒了要打印的变量的顺序,同时覆盖了输出的beguinning ..
要处理的所有源文本都是相同的。一个是通过路由器从sram上获取paramiko,另一个是我手动抓取并粘贴它作为局部变量。
当前输出:
with testis 10.8.11.72 from 10.8.11.72 (10.111.72.1)
使用静态局部变量的所需输出和输出:
Best Path is 10.8.11.73 from 10.8.11.73 (10.111.73.1) with localpref 120
我没有世俗的想法为什么会这样。请参阅下面的更多信息和执行。 帮助吗
代码:
import paramiko
router_channel.send('sh ip bgp 10.23.24.32\n')
buff = ''
best_test =()
while not buff.endswith('#'):
resp = router_channel.recv(99999)
buff += resp
#DMVPN variable Declaration.
bgp_show = buff
bgp_list = bgp_show.split('Local')
bgp_list.pop(0)
for x in bgp_list:
if 'best' in x:
best_list = x.split('\n')
for x in best_list:
best_list = [x.strip(' ') for x in best_list]
local_pref = best_list[2]
local_pref = local_pref.split(',')
local_pref = local_pref[2]
best_test = best_list[1]
print '********'
print buff
print '********'
print "Best Path is " + best_test + " with " + "test"
print '********'
执行代码:
dirp@localhost Test Python Scripts]$ python splice.py
********
sh ip bgp 10.23.24.32
BGP routing table entry for 10.23.24.32/28, version 367886
Paths: (6 available, best #5, table default)
Advertised to update-groups:
1 2 3 4 5 6 7
9
Refresh Epoch 1
Local, (Received from a RR-client)
10.8.111.73 from 10.8.111.73 (10.111.73.2)
Origin IGP, metric 0, localpref 105, valid, internal
rx pathid: 0, tx pathid: 0
Refresh Epoch 2
Local, (Received from a RR-client)
10.8.11.72 from 10.8.11.72 (10.111.72.1)
Origin IGP, metric 0, localpref 120, valid, internal, best
rx pathid: 0, tx pathid: 0x0
Refresh Epoch 3
Local, (Received from a RR-client)
10.8.11.73 from 10.8.11.73 (10.111.73.1)
Origin IGP, metric 0, localpref 110, valid, internal
rx pathid: 0, tx pathid: 0
router#
********
With testis 10.8.11.72 from 10.8.11.72 (10.111.72.1)
********
静态代码:
bgp_list = bgp.split('Local')
bgp_list.pop(0)
#pprint.pprint( bgp_list )
#print bgp_list[2]
for x in bgp_list:
if 'best' in x:
best_list = x.split('\n')
for x in best_list:
best_list = [x.strip(' ') for x in best_list]
local_pref = best_list[2]
local_pref = local_pref.split(',')
local_pref = local_pref[2]
print '********'
print bgp
print '********'
print "Best Path is " + best_list[1] + ' with' + local_pref
print '********'
未将其置于循环中但在本地分配变量时输出:
derp@localhost Test Python Scripts]$ python splitty1.py
********
sh ip bgp 10.23.24.32 | exclude local
BGP routing table entry for 10.23.24.32/28, version 122378
Advertised to update-groups:
1 2 3 4 5 6 7
9
Refresh Epoch 1
Local, (Received from a RR-client)
10.8.111.72 from 10.8.111.72 (10.111.72.2)
Origin IGP, metric 0, localpref 105, valid, internal
rx pathid: 0, tx pathid: 0
Refresh Epoch 1
Local, (Received from a RR-client)
10.8.11.72 from 10.8.11.72 (10.111.72.1)
Origin IGP, metric 0, localpref 110, valid, internal
rx pathid: 0, tx pathid: 0
Refresh Epoch 2
Local, (Received from a RR-client)
10.8.11.73 from 10.8.11.73 (10.111.73.1)
Origin IGP, metric 0, localpref 120, valid, internal, best
rx pathid: 0, tx pathid: 0x0
Refresh Epoch 2
Local
10.8.11.73 from 10.9.0.1 (10.15.1.41)
Origin IGP, metric 0, localpref 120, valid, internal
Originator: 10.111.73.1, Cluster list: 10.15.1.41
rx pathid: 0, tx pathid: 0
Refresh Epoch 2
Local
10.8.11.73 from 10.8.0.1 (10.15.1.41)
Origin IGP, metric 0, localpref 120, valid, internal
Originator: 10.111.73.1, Cluster list: 10.15.1.41
rx pathid: 0, tx pathid: 0
Refresh Epoch 2
Local, (Received from a RR-client)
10.8.111.73 from 10.8.111.73 (10.111.73.2)
Origin IGP, metric 0, localpref 115, valid, internal
rx pathid: 0, tx pathid: 0
********
Best Path is 10.8.11.73 from 10.8.11.73 (10.111.73.1) with localpref 120
********
[derp@localhost Test Python Scripts]$
答案 0 :(得分:4)
router_channel.recv
返回Windows格式文本,其中每一行以'\r\n'
结尾。但是您使用x.split('\n')
创建了一个列表。这意味着每一行(可能除了最后一行)都将以'\r'
结束。
在非Windows系统上,如果打印出'\r'
,则会将光标移回第1列而不会使行前进。所以,当你这样做时:
print "Best Path is " + best_test + " with " + "test"
您正在打印:
Best Path is blah blah blah\r with test
其中将出现:
with testis blah blah blah
最简单的解决方案是使用str.splitlines()
方法而不是str.split('\n')
。这会自动考虑Windows行结尾:
返回字符串中的行列表,在行边界处断开。此方法使用universal newlines方法分割线...
如果您点击该链接,它会解释通用换行符:
一种解释文本流的方式,其中所有以下内容都被识别为一行:Unix行尾约定
'\n'
,Windows约定'\r\n'
和旧的Macintosh约定'\r'
...
答案 1 :(得分:0)
这些线条让我感到不安 -
for x in best_list:
best_list = [x.strip(' ') for x in best_list]
您显然通过best_list中的值修改了循环内best_list的值。即使你认为你知道那是做什么的,我也不会。
尝试为"内部"使用不同的变量名称。 best_list,看看是否有任何修复。