它说我想念一个'},我不知道在哪里?我已经重新启动了eclipse,错误仍然存在......我有java的基础知识,但没有错?
if(args.length > 0)
{
print("Started with arguments:");
for(int i=0; i < args.length;i++)
{
print(args[i]);
}
for(int y=0; y < args.length;i++)
{
if(args[y].startsWith("PATH=") == true);
{
setEXEPath(args[y].substring(5));
} //<-- THIS line
else if(args[y].startsWith("DIRECTSTART=") == true)
{
if(args[y].substring(12).equals("true") == true)
{
enableWorking();
}
else
{
disableWorking();
}
}
}
}
答案 0 :(得分:1)
问题是;
之后的分号(if
):
if(args[y].startsWith("PATH=") == true);
让我们来看看java如何解释这个:
// If some condition, do nothing - the ; terminates the if
if(args[y].startsWith("PATH=") == true);
// An anonymous block that's always called.
// As noted above, the if have been terminated.
{
setEXEPath(args[y].substring(5));
}
// An else if!
// But this cannot be, as it does not follow an if's block!
// Hence, this is a syntax error.
else if(args[y].startsWith("DIRECTSTART=") == true)
答案 1 :(得分:0)
这是你的问题:
if(args[y].startsWith("PATH=") == true); <-- remove the semi colon