Question

如何从此阵列中删除Bob并刷新数组键，以便在删除Bob后Charlie键变为0而不是1？

//Insert: OK
var cars = [];
cars[cars.length] ="Bob";
cars[cars.length] ="Charlie";
cars[cars.length] ="Laura";
console.log( cars );

//Update: OK

function Update(input, upgrade) {
  for(var key in cars) {
    if(cars[key]===input) {
      cars[key] = upgrade;
    }
  }
}
Update("Bob", "Bob-sleeping");
console.log( cars );

// Now removing Bob-sleeping from the array which should show Charlie and Laura

Answer 1

使用splice：

cars.splice(0, 1);

0是删除条目的索引，1是要删除的条目数。

＆＃13;

"use strict";
var cars = [];
cars[cars.length] ="Bob";
cars[cars.length] ="Charlie";
cars[cars.length] ="Laura";

display("Before: " + cars.join(", "));

cars.splice(0, 1);

display("After: " + cars.join(", "));

function display(msg) {
  var p = document.createElement("p");
  p.innerHTML = String(msg);
  document.body.appendChild(p);
}

＆＃13;

如果您需要查找索引，即使是模糊的现代浏览器，您也可以使用indexOf（可以在真正的旧版本上进行填充）。因此，如果您从"Bob-sleeping"开始，那么：

var index = cars.indexOf("Bob-sleeping");
if (index !== -1) {
    cars.splice(index, 1);
}

＆＃13;

"use strict";
var cars = [];
cars[cars.length] ="Bob";
cars[cars.length] ="Charlie";
cars[cars.length] ="Laura";

display("Before: " + cars.join(", "));

var index = cars.indexOf("Bob"); // Or "Bob-sleeping", if you've `Update`d
if (index !== -1) {
  cars.splice(index, 1);
}


display("After: " + cars.join(", "));

function display(msg) {
  var p = document.createElement("p");
  p.innerHTML = String(msg);
  document.body.appendChild(p);
}

＆＃13;

Javascript - 如何从此数组中删除记录？

1 个答案: