如何从此代码中删除时间?

时间:2012-04-11 11:34:16

标签: javascript html date datepicker timepicker

我有这个代码来生成日期/时间选择器,但我只需要使用此代码的日期选择器元素。

如何从此代码中删除时间选择元素并仍然可以使用?

function show_calendar(str_target, str_datetime) {
var arr_months = ["January", "February", "March", "April", "May", "June",
    "July", "August", "September", "October", "November", "December"];
var week_days = ["Su", "Mo", "Tu", "We", "Th", "Fr", "Sa"];
var n_weekstart = 1; // day week starts from (normally 0 or 1)

var dt_datetime = (str_datetime == null || str_datetime =="" ?  new Date() : str2dt(str_datetime));
var dt_prev_month = new Date(dt_datetime);
dt_prev_month.setMonth(dt_datetime.getMonth()-1);
var dt_next_month = new Date(dt_datetime);
dt_next_month.setMonth(dt_datetime.getMonth()+1);
var dt_firstday = new Date(dt_datetime);
dt_firstday.setDate(1);
dt_firstday.setDate(1-(7+dt_firstday.getDay()-n_weekstart)%7);
var dt_lastday = new Date(dt_next_month);
dt_lastday.setDate(0);

var str_buffer = new String (
    "<html>\n"+
    "<head>\n"+
    "   <title>Calendar</title>\n"+
    "</head>\n"+
    "<body bgcolor=\"White\">\n"+
    "<table class=\"clsOTable\" cellspacing=\"0\" border=\"0\" width=\"100%\">\n"+
    "<tr><td bgcolor=\"#4682B4\">\n"+
    "<table cellspacing=\"1\" cellpadding=\"3\" border=\"0\" width=\"100%\">\n"+
    "<tr>\n <td bgcolor=\"#4682B4\"><a href=\"javascript:window.opener.show_calendar('"+
    str_target+"', '"+ dt2dtstr(dt_prev_month)+"'+document.cal.time.value);\">"+
    "<img src=\"prev.gif\" width=\"16\" height=\"16\" border=\"0\""+
    " alt=\"previous month\"></a></td>\n"+
    "   <td bgcolor=\"#4682B4\" colspan=\"5\">"+
    "<font color=\"white\" face=\"tahoma, verdana\" size=\"2\">"
    +arr_months[dt_datetime.getMonth()]+" "+dt_datetime.getFullYear()+"</font></td>\n"+
    "   <td bgcolor=\"#4682B4\" align=\"right\"><a href=\"javascript:window.opener.show_calendar('"
    +str_target+"', '"+dt2dtstr(dt_next_month)+"'+document.cal.time.value);\">"+
    "<img src=\"next.gif\" width=\"16\" height=\"16\" border=\"0\""+
    " alt=\"next month\"></a></td>\n</tr>\n"
);

var dt_current_day = new Date(dt_firstday);

str_buffer += "<tr>\n";
for (var n=0; n<7; n++)
    str_buffer += " <td bgcolor=\"#87CEFA\">"+
    "<font color=\"white\" face=\"tahoma, verdana\" size=\"2\">"+
    week_days[(n_weekstart+n)%7]+"</font></td>\n";

str_buffer += "</tr>\n";
while (dt_current_day.getMonth() == dt_datetime.getMonth() ||
    dt_current_day.getMonth() == dt_firstday.getMonth()) {

    str_buffer += "<tr>\n";
    for (var n_current_wday=0; n_current_wday<7; n_current_wday++) {
            if (dt_current_day.getDate() == dt_datetime.getDate() &&
                dt_current_day.getMonth() == dt_datetime.getMonth())

                str_buffer += " <td bgcolor=\"#FFB6C1\" align=\"right\">";
            else if (dt_current_day.getDay() == 0 || dt_current_day.getDay() == 6)

                str_buffer += " <td bgcolor=\"#DBEAF5\" align=\"right\">";
            else

                str_buffer += " <td bgcolor=\"white\" align=\"right\">";

            if (dt_current_day.getMonth() == dt_datetime.getMonth())

                str_buffer += "<a href=\"javascript:window.opener."+str_target+
                ".value='"+dt2dtstr(dt_current_day)+"'+document.cal.time.value; window.close();\">"+
                "<font color=\"black\" face=\"tahoma, verdana\" size=\"2\">";
            else 

                str_buffer += "<a href=\"javascript:window.opener."+str_target+
                ".value='"+dt2dtstr(dt_current_day)+"'+document.cal.time.value; window.close();\">"+
                "<font color=\"gray\" face=\"tahoma, verdana\" size=\"2\">";
            str_buffer += dt_current_day.getDate()+"</font></a></td>\n";
            dt_current_day.setDate(dt_current_day.getDate()+1);
    }

    str_buffer += "</tr>\n";
}

这部分是否有形式,但是当我将时间元素从表单中移出时,它无法正常工作?在我卸下时间选择器元素后,日期选择器将出现,但不会关闭!我该如何解决这个问题?

str_buffer +=
    "<form name=\"cal\">\n<tr><td colspan=\"7\" bgcolor=\"#87CEFA\">"+
    "<font color=\"White\" face=\"tahoma, verdana\" size=\"2\">"+
    "Time: <input type=\"text\" name=\"time\" value=\""+dt2tmstr(dt_datetime)+
    "\" size=\"8\" maxlength=\"8\"></font></td></tr>\n</form>\n" +
    "</table>\n" +
    "</tr>\n</td>\n</table>\n" +
    "</body>\n" +
    "</html>\n";

var vWinCal = window.open("", "Calendar", 
    "width=200,height=250,status=no,resizable=yes,top=200,left=200");
vWinCal.opener = self;
var calc_doc = vWinCal.document;
calc_doc.write (str_buffer);
calc_doc.close();
}


    function str2dt (str_datetime) {     
var re_date = /^(\d+)\-(\d+)\-(\d+)\s+(\d+)\:(\d+)\:(\d+)$/;
if (!re_date.exec(str_datetime))
    return alert("Invalid Datetime format: "+ str_datetime);
return (new Date (RegExp.$3, RegExp.$2-1, RegExp.$1, RegExp.$4, RegExp.$5,    RegExp.$6));
}
function dt2dtstr (dt_datetime) {
return (new String (
    dt_datetime.getFullYear()+"/"+(dt_datetime.getMonth()+1)+"/"+dt_datetime.getDate()));
 }
 function dt2tmstr (dt_datetime) {
return (new String (
dt_datetime.getHours()+":"+dt_datetime.getMinutes()+":"+dt_datetime.getSeconds()));
 }

2 个答案:

答案 0 :(得分:0)

很抱歉,但这段代码太可怕了。最好完全重写它。我建议:

  • 至少从数据和逻辑中单独呈现。最简单(虽然非常粗糙)的方法是将所有(格式化的)html保留在一个var中。不要追加/建立它。获取必要的数据包含元素并操纵它们,即(仅仅是一个概念):

    var $layout = $('<form>'+
                        '<div/>' +
                         ....
                    '</form>'),
        $dateInput = $layout.find('input[name="date"]');
    
    .....
    
    $dateInput.val(date);
    

  • 最好使用现有的数据采集解决方案

答案 1 :(得分:0)