Question

添加所有正数并将其置于变量中的程序并添加所有负数并将它们放在变量中。最后，该计划应该打印两个变量中的值，并计算两个变量的平均值。当用户键入零时，程序应该结束。

这是我到目前为止所做的。

int sumPositive, sumNegative;
int n, c = 1;

int main ()
{
    printf("Enter Positive integers:\n");
    scanf("%d", &n);
    for (c = 1; c <=n ; c++)
    {
        scanf("%d",&n);
        sumPositive = sumPositive + n;
    }
    printf("The value of positive numbers is: %d", sumPositive);

    return 0;   
}

Answer 1

您的循环应该使用while而不是因为您正在等待输入，而不是更改循环控制变量。所以：

int n, sumPositive = 0, sumNegative = 0;
scanf("%d", &n);
while (n != 0)
{
    //Do your calculations here
    scanf("%d", &n);
}

如果您愿意，还可以通过使用while（true）循环减少编写scanf的次数：

int n, sumPositive = 0, sumNegative = 0;
while(true)
{
    scanf("%d", &n);
    if (n == 0)
        break;
//Rest of calculations
}

正如Jonathan Leffler指出的那样，您应该检查scanf的结果，看看该值是否被正确读取。把它放在循环中的最简单方法是：

int n, sumPositive = 0, sumNegative = 0;
while(scanf("%d", &n) == 1 && n != 0)//Read an n value, check that the read was successful, then check that n != 0
{
//Rest of calculations
}

Answer 2

抓住：！）

#include <stdio.h>

int main( void )
{
    int x;
    int sumPositive   = 0, sumNegative   = 0;
    int countPositive = 0, countNegative = 0;

    printf( "Enter positive and negative integer numbers (0 - exit): " );

    while ( scanf( "%d", &x ) == 1 && x != 0 )
    {
        if ( x < 0 )
        {
            sumNegative += x;
            countNegative++;
        }
        else
        {
            sumPositive += x;
            countPositive++;
        }
    }

    printf( "\nSum of positive numbers is %d, and their average is %d\n",
            sumPositive, countPositive == 0 ? 0 : sumPositive / countPositive );

    printf( "\nSum of negative numbers is %d, and their average is %d\n",
            sumNegative, countNegative == 0 ? 0 : sumNegative / countNegative );

    return 0;
}

例如，如果要输入

1 -2 3 -4 5 -6 7 -8 9 0

然后输出

Sum of positive numbers is 25, and their average is 5

Sum of negative numbers is -20, and their average is -5

Answer 3

while( n != 0) //checking if the user has entered 0 or some other number
{
    scanf("%d",&n);
    //here you have to check whether the entered number is postive ( >0 ) or negative ( <0 )
    //and then accordingly you have to add it to sumPositive or sumNegative,
    //hint: if else will help you
}

创建一个C程序，总结没有数组的正数和负数？

3 个答案: