我需要帮助拉出数字并用逗号分隔它们,例如,如果我输入1 2 3 4 5,它应该打印出来
Entered Numbers: 1, 2, 3, 4, 5
The Sum: 15
相反,我得到了这个
Entered Numbers: 12345
The Sum: 15
代码:
/*A program that prompts the user to enter a positive integer number. The program should accept integers until the user enters the
value -1 (negative one). After the user enters -1, the program should display the entered numbers followed by their sum*/
import java.util.Scanner;
public class InputSum
{
public static void main(String [] args)
{
//create a way to receive user input
Scanner input = new Scanner(System.in);
//Variables
int sum = 0;
String value;
//Input
System.out.println("Enter a positive integer (Enter -1 to quit): ");
value = input.nextLine();
String x = "";
//Loop Statements
while (Integer.parseInt(value) != -1)
{
sum = Integer.parseInt(value) + sum;
x = x + value;
value = input.nextLine();
}
//Output
System.out.println("Entered Numbers: " + x);
System.out.println("The sum: " + sum);
}
}
答案 0 :(得分:0)
您可以使用replace()来执行您想要的操作。以这种格式使用它
value = value.replace(" ", ","); //First param is the char you want to replace; The second is the one you want to replace the first param with
答案 1 :(得分:0)
使用Split string方法获取每个数字,然后使用trim来获取带空格的限制。然后将该字符串粘贴到int中,并将其粘贴到总和中。只有循环部分发生了变化。其他一切都是一样的。
public static void main(String [] args)
{
//create a way to receive user input
Scanner input = new Scanner(System.in);
//Variables
int sum = 0;
String value;
//Input
System.out.println("Enter a positive integer (Enter -1 to quit): ");
value = input.nextLine();
for(String eachNum:value.split(",")) {
sum=Interger.parseInt(eachNum.trim());
}
//Output
System.out.println("Entered Numbers: " + value);
System.out.println("The sum: " + sum);
}
答案 2 :(得分:0)
替换
String x = "";
//Loop Statements
while (Integer.parseInt(value) != -1
{
sum = Integer.parseInt(value) + sum;
x = x + value;
value = input.nextLine();
}
带
String x = value;
//Loop Statements
while (Integer.parseInt(value) != -1)
{
sum = Integer.parseInt(value) + sum;
x = x + ", " + value;
value = input.nextLine();
}