Question

我试图解决这个问题时遇到了很多痛苦。所以，我要做的是创建源于一个父进程的3个子进程。我已经想到了，但问题是我的程序退出时，它到达第三个孩子让它成为孤儿（我想）。这是第一代流程的代码：

int i = 0;
int corpse;
int status;
pid_t child;
about("Dad");
printf("Now ..  Forking !!\n");

about("Dad");
for(i=0; i<3; i++){
child = fork();

  if (child == 0){

    about ("son");
    break;

  }else if (child < 0){

    perror ("Unable to fork!");
    break;
  }

}

void about(char * msg)
{
 pid_t me;
 pid_t old;

 me = getpid();
 old = getppid();

 printf("[%s] Hi, my pid is %d and I come from %d.\n", msg, me, old);
}
while ((corpse = wait(&status)) > 0){
    printf("Child process PID=%d terminates\n", corpse);
}

现在我的输出如下：

[Dad] Hi, my pid is 2940 and I come from 2883.
Now ..  Forking !!
[Dad] Hi, my pid is 2940 and I come from 2883.
[son] Hi, my pid is 2941 and I come from 2940.
[son] Hi, my pid is 2942 and I come from 2940.
Child process PID=2941 terminates
Child process PID=2942 terminates
[son] Hi, my pid is 2943 and I come from 2940.
Child process PID=2943 terminates

Answer 1

如果我能做对，你担心孩子过程变成孤儿，那么你可以使用等待或等待。通过使用其中任何一个，父进程可以等待子进程终止。如需更多帮助，请使用“man wait”。

fork函数涉及for循环

1 个答案: