我看了this你可以解释几件事吗? 我已经在终端的不同标签(3个标签页)中运行了 rpc_server.py 。
该教程中的rpc_server.py :
#!/usr/bin/env python
import pika
connection = pika.BlockingConnection(pika.ConnectionParameters(
host='localhost'))
channel = connection.channel()
channel.queue_declare(queue='rpc_queue')
def fib(n):
if n == 0:
return 0
elif n == 1:
return 1
else:
return fib(n-1) + fib(n-2)
def on_request(ch, method, props, body):
n = int(body)
print " [.] fib(%s)" % (n,)
response = fib(n)
ch.basic_publish(exchange='',
routing_key=props.reply_to,
properties=pika.BasicProperties(correlation_id = \
props.correlation_id),
body=str(response))
ch.basic_ack(delivery_tag = method.delivery_tag)
channel.basic_qos(prefetch_count=1)
channel.basic_consume(on_request, queue='rpc_queue')
print " [x] Awaiting RPC requests"
channel.start_consuming()
很好,我需要发送 send.py 3个请求:
#!/usr/bin/env python
import pika
import uuid
class FibonacciRpcClient(object):
def __init__(self):
self.connection = pika.BlockingConnection(pika.ConnectionParameters(
host='localhost'))
self.channel = self.connection.channel()
result = self.channel.queue_declare(exclusive=True)
self.callback_queue = result.method.queue
self.channel.basic_consume(self.on_response, no_ack=True,
queue=self.callback_queue)
def on_response(self, ch, method, props, body):
if self.corr_id == props.correlation_id:
self.response = body
def call(self, n):
self.response = None
self.corr_id = str(uuid.uuid4())
self.channel.basic_publish(exchange='',
routing_key='rpc_queue',
properties=pika.BasicProperties(
reply_to = self.callback_queue,
correlation_id = self.corr_id,
),
body=str(n))
while self.response is None:
self.connection.process_data_events()
return int(self.response)
fibonacci_rpc = FibonacciRpcClient()
print " [x] Requesting fib(30)"
response = fibonacci_rpc.call(30)
print " [.] Got %r" % (response,)
fibonacci_rpc1 = FibonacciRpcClient()
print " [x] Requesting fib(30)"
response1 = fibonacci_rpc1.call(30)
print " [.] Got %r" % (response1,)
fibonacci_rpc2 = FibonacciRpcClient()
print " [x] Requesting fib(30)"
response2 = fibonacci_rpc2.call(30)
print " [.] Got %r" % (response2,)
是否意味着脚本将等待第一个请求的响应,然后发送第二个请求,再次等待响应,然后发送第三个请求?
我想在一瞬间做3个请求,不等待响应然后发送新请求。这该怎么做?
我如何更改send.py
或使用其他技巧?我必须使用线程或多处理吗? RabbitMQ是否支持此功能?
谢谢!
答案 0 :(得分:0)
如果您希望一次发送所有三个请求,则需要使用线程。一个简单的解决方案看起来像这样:
import threading
from time import sleep
def make_rpc_call(value):
fibonacci_rpc = FibonacciRpcClient()
print " [x] Requesting fib({0})".format(value)
response = fibonacci_rpc.call(value)
print " [.] Got %r" % (response,)
for index in xrange(5):
thread_ = threading.Thread(target=make_rpc_call, args=(30, ))
thread_.start()
sleep(0.1)
请记住,Pika不是线程安全的,因此您需要为每个线程创建一个连接。作为替代方案,您可以查看我的Psk的Flask示例here。修改它很容易,允许您异步执行多个请求。
def rpc_call():
# Fire of all three requests.
corr_id1 = rpc_client.send_request('1')
corr_id2 = rpc_client.send_request('2')
corr_id3 = rpc_client.send_request('3')
# Wait for the response on all three requests.
while not rpc_client.queue[corr_id1] \
or not rpc_client.queue[corr_id2] \
or not rpc_client.queue[corr_id3]:
sleep(0.1)
# Print the result of all three requests.
print rpc_client.queue[corr_id1]
print rpc_client.queue[corr_id2]
print rpc_client.queue[corr_id3]
if __name__ == '__main__':
rpc_client = RpcClient('rpc_queue')
sleep(1)
print rpc_call()