Question

我正在编写一个程序，询问您是否要进行加法，减法，乘法和除法。然后它询问了多少问题。我有一切工作，但司。我想确保在进行除法问题时不会有余数。我不知道如何做这项工作。

      else if (player==4) {

      System.out.print("How many questions would you like?-->"); player =
      in.nextInt(); numQuestions= player;


      do{

      //question
          do {
              do{
          num1 = (int) (Math.random() * 100);
          num2 = (int) (Math.random() *10);

              }while (num2 > num1);
          } while (num1 % num2 == 0);


              compAnswer = num1 / num2;



                  System.out.println(num1+" / " + num2 + "=");                  
                  System.out.print("What's your answer? -->");
                  player = in.nextInt();
                    if (player == compAnswer) {
                        System.out.println(" That's right, the answer is "
                                + compAnswer);
                        System.out.println("");
                        score++;
                    } else {
                        System.out.println("That's wrong! The answer was "
                                + compAnswer);
                        System.out.println("");                     

                    }
            //x++;


      }while( x < numQuestions + 1 );

      System.out.println("");
      System.out.println("Thanks for playing! Your score was " + score +
      "."); }

Answer 1

您专门选择提醒的数字。你可以在有提醒时循环：

} while (num1 % num2 != 0);

然而，你根本不需要循环。如果选择第二个操作数和答案，则可以计算第一个操作数：

num2 = (int) (Math.random() *10);
compAnswer = (int) (Math.random() * 10);

num1 = num2 * compAnswer;

数学：分裂问题生成器

1 个答案: