Question

我需要在天数中找到当前日期时间LocalDateTIme.now()与另一个名为LocaDateTime的{{1}}对象之间的差异。也是从issueDateTime开始计算的天数。也就是说，如果issueDateTime是2014年4月12日下午5:00，那么应该计算为每个下午5点而不是上午12点。我想找出发布日期和当前日期之间的差异，然后将其与rentalTariff / day相乘，以返回方法issueDateTime的金额。谢谢

amountPayable()

Answer 1

您可以使用ChronoUnit.DAYS。比较LocalTime值，看看是否应该考虑开始“第二天”：

import java.time.*;
import java.time.temporal.*;

class Test {
    public static void main(String[] args) {
        // Start time before end time
        showDiff(2014, 9, 25, 15, 0,
                 2014, 9, 27, 17, 0);
        // Start time equal to end time
        showDiff(2014, 9, 25, 17, 0,
                 2014, 9, 27, 17, 0);
        // Start time later than end time
        showDiff(2014, 9, 25, 18, 0,
                 2014, 9, 27, 17, 0);
    }

    public static void showDiff(
        int startYear, int startMonth, int startDay,
        int startHour, int startMinute,
        int endYear, int endMonth, int endDay,
        int endHour, int endMinute) {
        LocalDateTime start = LocalDateTime.of(
            startYear, startMonth, startDay, startHour, startMinute);
        LocalDateTime end = LocalDateTime.of(
            endYear, endMonth, endDay, endHour, endMinute);

        System.out.printf("%s to %s is %d day(s)%n", start, end,
            differenceInDays(start, end));
    }

    public static int differenceInDays(LocalDateTime start, LocalDateTime end) {
        LocalDate startDate = start.toLocalDate();
        LocalDate endDate = end.toLocalDate();
        if (start.toLocalTime().isAfter(end.toLocalTime())) {
            startDate = startDate.plusDays(1);
        }
        return (int) ChronoUnit.DAYS.between(startDate, endDate);
    }
}

输出：

2014-09-25T15:00 to 2014-09-27T17:00 is 2 day(s)
2014-09-25T17:00 to 2014-09-27T17:00 is 2 day(s)
2014-09-25T18:00 to 2014-09-27T17:00 is 1 day(s)

Answer 2

使用LocalDateTime中的某一天来计算。考虑到原始日期时间可能在当前日期之后，如果年份有差异。（这将导致负面结果）

两天的LocalDateTIme对象之间的差异

2 个答案: