如何使此方法返回布尔值,具体取决于查询返回。假 - 没有,真实 - 数据存在。在我从uniqueQuote.Count()返回int之前,但看起来不是很好的方法。谢谢!
private bool CheckEnquiryUser(int enquiryId, Guid userId)
{
int selectedEnquiryId = enquiryId;
Guid currentUserId = userId;
Entities ctx3 = new Entities();
var uniqueQuote = from quot in ctx3.Enquiries.Include("aspnet_Users")
where quot.EnquiryId == selectedEnquiryId &&
quot.aspnet_Users.UserId == currentUserId
select quot;
bool exist = uniqueQuote;
return exist;
答案 0 :(得分:1)
return uniqueQuote.Any();
或直接将谓词传递给它:
return ctx3.Enquiries.Include("aspnet_Users")
.Any(quot => quot.EnquiryId == selectedEnquiryId
&& quot.aspnet_Users.UserId == currentUserId);
答案 1 :(得分:1)
我更习惯这种格式,但您可以翻译为使用.Any
return ctx3.Enquiries.Include("aspnet_Users")
.Any(x=> x.EnquiryId == selectedEnquiryId &&
x.aspnet_Users.UserId == currentUserId);
答案 2 :(得分:0)
尝试类似:
return uniqueQuote.Count() > 0;