Question

如何编辑

的公式

weekday=(day+2(month)+3(month)/5+year+year/4-year/100+year/400)/7

这样我就不会收到错误消息，说“表达式不能用作函数”？

#include <iostream>
using namespace std;
int main()
{
int date=0;
int month=0;
int day=0;
int year=0;
int leftover=0;
int weekday=0;

cout<<"Enter Date (ex.20140912) :";
cin>>date;

year=date/10000;
leftover=date%10000;
month=leftover/100;
day=date%100;
{
if (month==3)
    {cout<<"March "<< day<<", "<< year<<":";
        weekday=(day+2(month)+3(month)/5+year+year/4-year/100+year/400)/7;

            if (weekday==0)
                {cout<<"Saturday";
                }
            if (weekday==1)
                {cout<<"Sunday";
                }
            if (weekday==2)
                {cout<<"Monday";
                }
            if (weekday==3)
                {cout<<"Tuesday";
                }
            if (weekday==4)
                {cout<<"Wednesday";
                }

Answer 1

代码2(month)是函数调用语法，好像2是一个函数......但事实并非如此。你是否意味着乘法，例如2 * month？

Answer 2

您需要输入运算符（*）进行乘法运算：

weekday=(day+2*(month)+3*(month)/5+year+year/4-year/100+year/400)/7;

如果操作符丢失，则c（++）将其解释为函数调用，其中函数名称为例如2。

C ++错误表达式不能用作函数

2 个答案: