Question

我正在尝试根据用户输入字符串 推文和解析推文文本，从推文中提取网络链接（忽略没有网络链接的推文）并解析它以在下一个按钮的WebView对话框中显示（因此当单击以移动到下一个WebView（显示从推文解析的链接的下一个内容））。我得到推文结果（没有过滤），我如何过滤它们并获取URL，以便我可以为WebView解析它？

以下是我在后台线程上运行的代码：

 @Override
            protected WebView doInBackground(String... strings) {
                //Get userInput
                String searchTerm = strings[0];
                //Initialize Twitter Connection
                ConfigurationBuilder builder = new ConfigurationBuilder();
                    builder.setDebugEnabled(true);
                    builder.setOAuthConsumerKey(sharedPreferences.getString(TwitterConstants.getPrefConsumerKey(), ""));
                    builder.setOAuthConsumerSecret(sharedPreferences.getString(TwitterConstants.getPrefConsumerSecret(), ""));
                AccessToken accessToken = new AccessToken(sharedPreferences.getString(TwitterConstants.getPrefAccessToken(), ""), sharedPreferences.getString(TwitterConstants.getPrefAccessTokenSecret(), ""));
                Twitter twitter = new TwitterFactory(builder.build()).getInstance(accessToken);
                try {
                    //Query object
                    Query query = new Query(searchTerm);
                    //The number of tweets to return per page [max:100]
                    query.count(2);
                    //Return only the most recent results in the response
                    query.resultType(Query.ResultType.recent);
                    QueryResult result = twitter.search(query);
                    Log.e("Twitter QueryResult", result.toString());
                }catch(TwitterException e){
                    e.printStackTrace();
                }
                return null;
            }

Answer 1

好的，如果有人遇到同样的问题，答案就是答案：

 @Override
        protected WebView doInBackground(String... strings) {
            //Get userInput
            String searchTerm = strings[0];
            //Initialize Twitter Connection
            ConfigurationBuilder builder = new ConfigurationBuilder();
                builder.setDebugEnabled(true);
                builder.setOAuthConsumerKey(sharedPreferences.getString(TwitterConstants.getPrefConsumerKey(), ""));
                builder.setOAuthConsumerSecret(sharedPreferences.getString(TwitterConstants.getPrefConsumerSecret(), ""));
            AccessToken accessToken = new AccessToken(sharedPreferences.getString(TwitterConstants.getPrefAccessToken(), ""), sharedPreferences.getString(TwitterConstants.getPrefAccessTokenSecret(), ""));
           //Gets Twitter instance with default credentials
            Twitter twitter = new TwitterFactory(builder.build()).getInstance(accessToken);
            try {
                //Query object
                Query query = new Query(searchTerm);
                //The number of tweets to return per page [max:100]
                query.count(2);
                //Return only the most recent results in the response
                query.resultType(Query.ResultType.recent);
                //Get all results
                QueryResult result = twitter.search(query);
                //Fetch only tweets from the results
                List<twitter4j.Status> tweets = result.getTweets();

                for(twitter4j.Status tweet : tweets){
                    //Get single tweet
                    String singleTweet = tweet.getText();
                    Log.e("Twitter Tweet", singleTweet);
                    //Get URLs (it returns an array of Urls)
                    URLEntity[] urlEntity = tweet.getURLEntities();
                    //If the UrlEntity array is not empty
                    if(urlEntity != null){
                        for(int i=0; i<urlEntity.length; i++){
                            //Get URL from the tweet
                            String tweetUrl = urlEntity[i].getURL();
                            Log.e("Tweet URL", tweetUrl);
                        }
                    }else{
                        return null;
                    }
                }

            }catch(TwitterException e){
                e.printStackTrace();
            }
            return null;
        }

        @Override
        protected void onPostExecute(WebView webView) {
            progressDialog.hide();
        }
    }

Answer 2

如果您使用的是twitter4j库，则可以通过调用URLEntity从twitter4j.Status获取status.getURLEntities();类。这将返回URLEntity的数组。所以，你去，你可以检查推文里面是否有urlEntity，你可以通过调用urlEntity.getURL();来获取推文中提到的网址

修改对于包含代码的答案，请看下面的@hrskrs的答案。

使用Twitter4j-4.0.2消费和过滤推文

2 个答案: