使用Twitter4j获取推文

时间:2015-05-06 17:51:15

标签: java twitter twitter4j

我有一个用于获取推文的java程序,下面是代码

public class TwitterTest {
    public static void main(String[] args) {
        Twitter twitter = new TwitterFactory().getInstance();

        //  My Applications Consumer and Auth Access Token
        //twitter.setOAuthConsumer("67MIcbC1X6mbpaEqxa7YTd1hDPIdLb5bLKf4TxIRLAsX63DgFQ", "7HHjSHJ6Rjxx4ASC2465AlWBG");
        twitter.setOAuthAccessToken(new AccessToken("s1y1iAhG5nsXTrE9OVAsqMtqiLIP4QKT8CmTRVgV9LC3O", "110445397-Cf3l9NAK4iD8VAERXp0ZMKnAfWx9KywuJs3OSdkF"));

        try {

            ResponseList<Status> a = twitter.getUserTimeline(new Paging(1,5));

            for(Status b: a) {
                System.out.println(b.getText());
            }

        }catch(Exception e ){

        }

    }
}

以下是我得到的错误

Relevant discussions can be found on the Internet at:
http://www.google.co.jp/search?q=b64d2231 or
http://www.google.co.jp/search?q=309f0452
TwitterException{exceptionCode=[b64d2231-309f0452], statusCode=403,     message=SSL is required, code=92, retryAfter=-1,    rateLimitStatus=RateLimitStatusJSONImpl{remaining=178, limit=180, resetTimeInSeconds=1430935706, secondsUntilReset=775}, version=3.0.3}

错误的原因是什么?

1 个答案:

答案 0 :(得分:2)

您需要设置启用SSL。请查看此主题以获取更多信息:"SSL is required" exception while requesting OAuthRequest Token using Twitter4J library