Question

TakenOn是日期时间列

使用

程序

;WITH TBL AS
  (SELECT CONVERT(date,TakenOn) AS Date,
          COUNT(*) AS 'NewSubs'
   FROM Urls (NOLOCK)
   WHERE FId = 11
     AND (TakenOn >= @StartDate)
     AND (TakenOn <= @EndDate)
   GROUP BY CONVERT(date,TakenOn))
SELECT t1.Date, t1.NewSubs,
                SUM(t1.NewSubs) AS 'TotalSubs'
FROM TBL t1
INNER JOIN TBL t2 ON t1.Date >= t2.Date
GROUP BY t1.Date, t1.NewSubs

输出为：//（这对我来说是错误的）

Date       NewSubs  TotalSubs
2014-09-19  2        2
2014-09-20  3        6
2014-09-21  1        3
2014-09-22  4        16

我应该将输出更改为

Date       NewSubs  TotalSubs
2014-09-19  2        2
2014-09-20  3        5
2014-09-21  1        6
2014-09-22  4        10

Answer 1

试试这个：SUM(t1.NewSubs) over(order by t1.Date)

例如：

;WITH TBL AS
  (SELECT CONVERT(date,TakenOn) AS Date,
          COUNT(*) AS 'NewSubs'
   FROM Urls (NOLOCK)
   WHERE FId = 11
     AND (TakenOn >= @StartDate)
     AND (TakenOn <= @EndDate)
   GROUP BY CONVERT(date,TakenOn))
SELECT t1.Date, t1.NewSubs,
                SUM(t1.NewSubs) over(order by t1.Date) AS 'TotalSubs'
FROM TBL t1
INNER JOIN TBL t2 ON t1.Date >= t2.Date
GROUP BY t1.Date, t1.NewSubs

在日期的情况下，sql中的累积总和

1 个答案: