Question

我有一个很大的（会员）会员数据库，我在这里尝试做一些将来的会员计划。因此，我试图获取每月每月输入到系统的成员总数。

我有以下代码

select  YEAR(datejoined) as YDJ,
    MONTH(datejoined) as MDJ,
    COUNT(MONTH(datejoined)) as CDJ,
    SUM(Count(Month(DateJoined))) as SCDJ
From Member
Group by YEAR(datejoined), MONTH(datejoined)
Order by YEAR(DateJoined) asc, MONTH(datejoined) asc;

但是它会引发如下错误：

第15层状态1的第4行消息130 无法对包含聚合或子查询的表达式执行聚合功能。

我希望SUM函数要做的是计算从开始到该点（包括该月的新成员）中DB中的成员总数。

Answer 1

根据您的描述，我认为您想要

select YEAR(datejoined) as YDJ, MONTH(datejoined) as MDJ,
       COUNT(*) as CDJ,
       SUM(COUNT(*)) OVER (ORDER BY YEAR(datejoined), MONTH(datejoined)) as running_CDJ
    SUM(Count(Month(DateJoined))) as SCDJ
From Member
Group by YEAR(datejoined), MONTH(datejoined)
Order by YEAR(DateJoined) asc, MONTH(datejoined) asc;

SQL Server 2012+中提供了累计金额。在早期版本中，您可以使用APPLY：

with t as (
      select YEAR(datejoined) as YDJ, MONTH(datejoined) as MDJ,
             COUNT(*) as CDJ,
             SUM(COUNT(*)) OVER (ORDER BY YEAR(datejoined), MONTH(datejoined)) as running_CDJ
      From Member
      Group by YEAR(datejoined), MONTH(datejoined)
     )
select t.*, t2.running_cdj
from t outer apply
     (select sum(CDJ) as running_CDJ
      from t t2
      where t2.ydj < t.ydj or
            t2.ydj = t.ydj and t2.mdj <= t2.mdj
     ) t2;

Answer 2

由SUM(Count(Month(DateJoined))) as SCDJ

引起的错误

聚合函数一次不能包含聚合函数。

您需要编写子查询来解决

如果要累积总和，则可以将窗口功能与SUM

一起使用

SELECT t.*,SUM(CDJ) OVER (ORDER BY YDJ ,MDJ) as SCDJ
FROM (
    select  
        YEAR(datejoined) as YDJ,
        MONTH(datejoined) as MDJ,
        COUNT(datejoined) as CDJ
    From Member
    Group by YEAR(datejoined), MONTH(datejoined)
) t 
Order by YDJ asc, 
         MDJ asc

运行累积总和

2 个答案: