Question

我的程序：从用户那里获取有关个人详细信息的输入，然后输出信息。

我的问题：程序无法计算位数作为电话号码字段的输入。它接受超过10位数作为电话号码的输入。

我的目标：检查“电话号码”的输入，并确保该号码为10位数。

我的代码：

#include <iostream>
#include <string>
#include <limits>

using namespace std;

class Personal_Details
{
public:
    void setFirstName   (string newFirstName);
    void setLastName    (string newLastName);
    void setBirthdate   (int newBirthday);
    void setEMail       (string newEMail);
    void setPhoneNumber (int newPhoneNumber);
    void QUESTIONS();
    string getFirstName();
    string getLastName();
    string getEMail();
    int getPhoneNumber();
    int    getBirthdate();

private:
    string FirstName;
    string LastName;
    string EMail;
    int PhoneNumber;
    int Birthdate;
};

void Personal_Details :: setFirstName (string newFirstName)
{
    FirstName = newFirstName;
}

void Personal_Details :: setLastName (string newLastName)
{
    LastName = newLastName;
}

void Personal_Details :: setBirthdate (int newBirthdate)
{
    Birthdate = newBirthdate;
}

void Personal_Details :: setEMail (string newEMail)
{
    EMail = newEMail;
}

void Personal_Details :: setPhoneNumber (int newPhoneNumber)
{
    PhoneNumber = newPhoneNumber;
}

string Personal_Details :: getFirstName()
{
    return FirstName;
}

string Personal_Details :: getLastName()
{
    return LastName;
}

int Personal_Details :: getBirthdate()
{
    return Birthdate;
}

string Personal_Details :: getEMail()
{
    return EMail;
}

int Personal_Details :: getPhoneNumber()
{
    if (PhoneNumber>12)
    {
        cout <<"INVALID. Program will now close.";
    }
    system ("PAUSE");

    return PhoneNumber;
}

void Personal_Details :: QUESTIONS()
{
    cout << "A.) Enter the following details:-" << endl <<endl;
    cout << "First Name: ";
    getline (cin, FirstName);
    cout << endl;

    cout << "Last (Family) Name: ";
    getline (cin, LastName);
    cout << endl;

    cout << "Birthdate: ";
    cin >> Birthdate;
    std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
    cout << endl;

    cout << "Email Address: ";
    getline (cin, EMail);
    cout << endl;

    cout << "Phone Number: ";
    cin >> PhoneNumber;
    cout << endl;

    cout<< FirstName <<" "<< LastName << endl 
        <<"Birthdate: "<< Birthdate << endl 
        <<"Email ID: "<< EMail << endl 
        <<"Phone Number: "<< PhoneNumber << endl;
}

int main()
{
    Personal_Details NewContact;
    cout << "- Add New Contact Information -" << endl << endl; 
    cout << "Note: Please type in only intergers (numbers) for 'Birthdate' and 'Phone Number' field. Also, phone number should be less than/or equal to 10 digits." << endl;
    cout << "Else, this program will terminate abruptly." << endl << endl;
    NewContact.QUESTIONS();
    cout << endl << endl;

    cout << "Press Any Key to Exit.";
    cin.ignore();
    cin.get();

    return 0;
}

请您查看并检查我无法输入真正的10位数电话号码的原因？我是C ++的新手，所以我无法找到解决方案。谢谢你的帮助！

Answer 1

您将电话号码存储为int，但整数范围为-2,147,483,648至2,147,483,647;输入超出该范围的10位数字会导致溢出，可能会导致程序崩溃。

您可能希望将电话号码作为字符串读取，检查每个字符的有效性，然后根据需要进行处理（例如：区号的变量，7位数的变量，拒绝超出范围输入并重新提示）。

无法计算数字作为输入

1 个答案: