取消按键事件

时间:2010-04-07 09:27:10

标签: c# wpf

如何返回密钥?,意思是如果我只想在文本框中只允许整数值,我怎么能不允许用户输入非整数,关于KeyPress事件,我知道还有其他方法,如表达式匹配字符串值,但我不想将无效值分配给文本框。

if (( value >0 a&&(value <=9)) then 
    assigned
else 
    return

7 个答案:

答案 0 :(得分:17)

使用Handled Property

e.Handled = true;

来自MSDN的示例:link

// Boolean flag used to determine when a character other than a number is entered.
private bool nonNumberEntered = false;

// Handle the KeyDown event to determine the type of character entered into the control.
private void textBox1_KeyDown(object sender, System.Windows.Forms.KeyEventArgs e)
{
    // Initialize the flag to false.
    nonNumberEntered = false;

    // Determine whether the keystroke is a number from the top of the keyboard.
    if (e.KeyCode < Keys.D0 || e.KeyCode > Keys.D9)
    {
        // Determine whether the keystroke is a number from the keypad.
        if (e.KeyCode < Keys.NumPad0 || e.KeyCode > Keys.NumPad9)
        {
            // Determine whether the keystroke is a backspace.
            if(e.KeyCode != Keys.Back)
            {
                // A non-numerical keystroke was pressed.
                // Set the flag to true and evaluate in KeyPress event.
                nonNumberEntered = true;
            }
        }
    }
    //If shift key was pressed, it's not a number.
    if (Control.ModifierKeys == Keys.Shift) {
        nonNumberEntered = true;
    }
}

// This event occurs after the KeyDown event and can be used to prevent
// characters from entering the control.
private void textBox1_KeyPress(object sender, System.Windows.Forms.KeyPressEventArgs e)
{
    // Check for the flag being set in the KeyDown event.
    if (nonNumberEntered == true)
    {
        // Stop the character from being entered into the control since it is non-numerical.
        e.Handled = true;
    }
}

答案 1 :(得分:7)

您可以使用如下的按键事件。使用e.Handled为true取消用户输入

    private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
    {
        if (!Char.IsDigit(e.KeyChar)) e.Handled = true;
    }

答案 2 :(得分:7)

创建一个字符串,其中包含允许用户输入的字符。

使用KeyDownKeyUp处理特殊键

private void tbN1_KeyPress(object sender, KeyPressEventArgs e)
{
    String sKeys = "1234567890ABCDEF";
    if (!sKeys.Contains(e.KeyChar.ToString().ToUpper()))
        e.Handled = true;
}

答案 3 :(得分:1)

从技术上讲,这是错误的,因为你标记了你的问题WPF。但是,由于您接受了其他Windows窗体的答案,我将发布我的解决方案,该解决方案适用于实数而不是整数。它也被本地化为仅接受当前语言环境的小数分隔符。

private void doubleTextBox_KeyPress (object sender, KeyPressEventArgs e)
{
  var textBox = sender as TextBoxBase;
  if (textBox == null)
      return;

  // did the user press their locale's decimal separator?
  if (e.KeyChar.ToString() == CultureInfo.CurrentCulture.NumberFormat.NumberDecimalSeparator)
  {
      if (textBox.Text.Length == 0) // if empty, prefix the decimal with a 0
      {
          textBox.Text = "0" + CultureInfo.CurrentCulture.NumberFormat.NumberDecimalSeparator;
          e.Handled = true;
          textBox.SelectionStart = textBox.TextLength;
      }
      // ignore extra decimal separators
      else if (textBox.Text.Contains(CultureInfo.CurrentCulture.NumberFormat.NumberDecimalSeparator))
          e.Handled = true;
  }
  // allow backspaces, but no other non-numeric characters;
  // note that arrow keys, delete, home, end, etc. do not trigger KeyPress
  else if (e.KeyChar != '\b' && (e.KeyChar < '0' || e.KeyChar > '9'))
      e.Handled = true;
}

答案 4 :(得分:1)

对于WPF,将PreviewTextInput事件与以下代码一起使用:

// Filter out non-numeric keys.
private void MyApp_PreviewTextInput(object sender, TextCompositionEventArgs e)
{
String sKeys = "1234567890";
if (!sKeys.Contains(e.Text))
    e.Handled = true;
}

答案 5 :(得分:0)

您可以使用MaskedTextBox并强制它仅为整数。

答案 6 :(得分:0)

您可以从TextBox继承,然后:

Protected Overrides Sub OnTextInput(ByVal e As System.Windows.Input.TextCompositionEventArgs)

        Dim newChar As Char = Convert.ToChar(e.Text)
        If Not [Char].IsDigit(newChar) Then e.Handled = True

End Sub

C#版

protected override void OnTextInput(System.Windows.Input.TextCompositionEventArgs e)
{    
    char newChar = Convert.ToChar(e.Text);        
    if (!Char.IsDigit(newChar)) e.Handled = true; 
}