在我的媒体播放器中,我添加了一个显示如果按下菜单键的视图,我希望它在一段时间后隐藏,即用户不想看到视图,视图是水平的,我想要它在几秒钟后隐藏,用户不会按向右或向左键。
我把我的逻辑放在这里,但它没有成功: “我的观点类似于”
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
super.onKeyDown(keyCode, event);
lastUsed = System.currentTimeMillis();
case KeyEvent.KEYCODE_MENU:
similar.setVisibility(View.VISIBLE);
similar.bringToFront();
similar.requestFocus();
similar.bringToFront();
nowHide()
}
public void nowHide(){
new Thread(new Runnable() {
public void run() {
while(true){
try {
Thread.sleep(5000);
} catch (InterruptedException e) {
e.printStackTrace();
}
if(getLastInteractionTime()+5000 >= System.currentTimeMillis())
{
Log.d("MOVIE PLAY ACTIVITY:SADIP", "check time success");
runOnUiThread(new Runnable() {
public void run() {
similar.setVisibility(View.GONE);
}
});
}
}
}
}).start();
}
public long getLastInteractionTime() {
return lastUsed;
}
public long setLastInteractionTime(int lastInteraction) {
lastUsed = lastInteraction;
return lastUsed;
}
代码从未到达
if(getLastInteractionTime()+5000 >= System.currentTimeMillis())
而且我也没有想到停止这个帖子
我该怎么做? 任何其他方法将不胜感激 提前谢谢。
答案 0 :(得分:8)
试试这个。它将在5秒后通过用户的吐司通知。 onUserInteraction 方法是此代码的主要部分。
Handler handler;
Runnable r;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
handler = new Handler();
r = new Runnable() {
@Override
public void run() {
// TODO Auto-generated method stub
Toast.makeText(MainActivity.this, "user inactive",
Toast.LENGTH_SHORT).show();
}
};
startHandler();
}
@Override
public void onUserInteraction() {
// TODO Auto-generated method stub
super.onUserInteraction();
stopHandler();//stop first and then start
startHandler();
}
public void stopHandler() {
handler.removeCallbacks(r);
}
public void startHandler() {
handler.postDelayed(r, 5000);
}