用户启动我的应用并登录。
选择会话超时为5分钟
在应用程序上执行某些操作。 (全部在前景)
现在用户将Myapp带到后台并启动其他应用程序。
---->倒数计时器启动并在5分钟后注销用户
或者用户关闭屏幕
---->倒计时器启动并在5分钟后注销用户
即使应用程序位于前台,我也想要相同的行为,但用户不会长时间与应用程序交互6到7分钟。假设屏幕始终处于开启状态。我想检测一下用户不活动(即使应用程序位于前台,也没有与应用程序进行交互)并启动我的倒数计时器。
答案 0 :(得分:96)
根据Fredrik Wallenius的回答,我想出了一个很简单的解决方案。这是一个需要由所有活动扩展的基本活动类。
public class MyBaseActivity extends Activity {
public static final long DISCONNECT_TIMEOUT = 300000; // 5 min = 5 * 60 * 1000 ms
private Handler disconnectHandler = new Handler(new Handler.Callback() {
@Override
public boolean handleMessage(Message msg) {
// todo
return true;
}
});
private Runnable disconnectCallback = new Runnable() {
@Override
public void run() {
// Perform any required operation on disconnect
}
};
public void resetDisconnectTimer(){
disconnectHandler.removeCallbacks(disconnectCallback);
disconnectHandler.postDelayed(disconnectCallback, DISCONNECT_TIMEOUT);
}
public void stopDisconnectTimer(){
disconnectHandler.removeCallbacks(disconnectCallback);
}
@Override
public void onUserInteraction(){
resetDisconnectTimer();
}
@Override
public void onResume() {
super.onResume();
resetDisconnectTimer();
}
@Override
public void onStop() {
super.onStop();
stopDisconnectTimer();
}
}
答案 1 :(得分:79)
我不知道跟踪不活动的方法,但有一种方法可以跟踪用户活动。您可以在活动中捕获名为onUserInteraction()
的回调,每次用户与应用程序进行任何交互时都会调用该回调。我建议做这样的事情:
@Override
public void onUserInteraction(){
MyTimerClass.getInstance().resetTimer();
}
如果您的应用包含多个活动,为什么不将此方法放在抽象超类中(扩展Activity
),然后让所有活动扩展它。
答案 2 :(得分:14)
我认为你应该使用这段代码,这是5分钟的空闲会话超时: - >
Handler handler;
Runnable r;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
handler = new Handler();
r = new Runnable() {
@Override
public void run() {
// TODO Auto-generated method stub
Toast.makeText(MainActivity.this, "user is inactive from last 5 minutes",Toast.LENGTH_SHORT).show();
}
};
startHandler();
}
@Override
public void onUserInteraction() {
// TODO Auto-generated method stub
super.onUserInteraction();
stopHandler();//stop first and then start
startHandler();
}
public void stopHandler() {
handler.removeCallbacks(r);
}
public void startHandler() {
handler.postDelayed(r, 5*60*1000); //for 5 minutes
}
答案 3 :(得分:8)
public class MyApplication extends Application {
private int lastInteractionTime;
private Boolean isScreenOff = false;
public void onCreate() {
super.onCreate();
// ......
startUserInactivityDetectThread(); // start the thread to detect inactivity
new ScreenReceiver(); // creating receive SCREEN_OFF and SCREEN_ON broadcast msgs from the device.
}
public void startUserInactivityDetectThread() {
new Thread(new Runnable() {
@Override
public void run() {
while(true) {
Thread.sleep(15000); // checks every 15sec for inactivity
if(isScreenOff || getLastInteractionTime()> 120000 || !isInForeGrnd)
{
//...... means USER has been INACTIVE over a period of
// and you do your stuff like log the user out
}
}
}
}).start();
}
public long getLastInteractionTime() {
return lastInteractionTime;
}
public void setLastInteractionTime(int lastInteractionTime) {
this.lastInteractionTime = lastInteractionTime;
}
private class ScreenReceiver extends BroadcastReceiver {
protected ScreenReceiver() {
// register receiver that handles screen on and screen off logic
IntentFilter filter = new IntentFilter();
filter.addAction(Intent.ACTION_SCREEN_ON);
filter.addAction(Intent.ACTION_SCREEN_OFF);
registerReceiver(this, filter);
}
@Override
public void onReceive(Context context, Intent intent) {
if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {
isScreenOff = true;
} else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {
isScreenOff = false;
}
}
}
}
isInForeGrnd ===>这里没有显示逻辑,因为它超出了问题的范围
您可以使用下面的设备代码将锁定唤醒到cpu -
if(isScreenOff || getLastInteractionTime()> 120000 || !isInForeGrnd)
{
//...... means USER has been INACTIVE over a period of
// and you do your stuff like log the user out
PowerManager pm = (PowerManager) context.getSystemService(Context.POWER_SERVICE);
boolean isScreenOn = pm.isScreenOn();
Log.e("screen on.................................", "" + isScreenOn);
if (isScreenOn == false) {
PowerManager.WakeLock wl = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK | PowerManager.ACQUIRE_CAUSES_WAKEUP | PowerManager.ON_AFTER_RELEASE, "MyLock");
wl.acquire(10000);
PowerManager.WakeLock wl_cpu = pm.newWakeLock(PowerManager.PARTIAL_WAKE_LOCK, "MyCpuLock");
wl_cpu.acquire(10000);
}
}
答案 4 :(得分:6)
@Override
public void onUserInteraction() {
super.onUserInteraction();
delayedIdle(IDLE_DELAY_MINUTES);
}
Handler _idleHandler = new Handler();
Runnable _idleRunnable = new Runnable() {
@Override
public void run() {
//handle your IDLE state
}
};
private void delayedIdle(int delayMinutes) {
_idleHandler.removeCallbacks(_idleRunnable);
_idleHandler.postDelayed(_idleRunnable, (delayMinutes * 1000 * 60));
}
答案 5 :(得分:4)
除了ACTION_SCREEN_OFF
和ACTION_USER_PRESENT
广播之外,在操作系统级别没有“用户不活动”的概念。您必须在自己的应用程序中以某种方式定义“不活动”。
答案 6 :(得分:3)
在我的活动基类中,我创建了受保护的类:
protected class IdleTimer
{
private Boolean isTimerRunning;
private IIdleCallback idleCallback;
private int maxIdleTime;
private Timer timer;
public IdleTimer(int maxInactivityTime, IIdleCallback callback)
{
maxIdleTime = maxInactivityTime;
idleCallback = callback;
}
/*
* creates new timer with idleTimer params and schedules a task
*/
public void startIdleTimer()
{
timer = new Timer();
timer.schedule(new TimerTask() {
@Override
public void run() {
idleCallback.inactivityDetected();
}
}, maxIdleTime);
isTimerRunning = true;
}
/*
* schedules new idle timer, call this to reset timer
*/
public void restartIdleTimer()
{
stopIdleTimer();
startIdleTimer();
}
/*
* stops idle timer, canceling all scheduled tasks in it
*/
public void stopIdleTimer()
{
timer.cancel();
isTimerRunning = false;
}
/*
* check current state of timer
* @return boolean isTimerRunning
*/
public boolean checkIsTimerRunning()
{
return isTimerRunning;
}
}
protected interface IIdleCallback
{
public void inactivityDetected();
}
所以在 onResume 方法中 - 您可以在回调中指定操作,您希望用它做什么...
idleTimer = new IdleTimer(60000, new IIdleCallback() {
@Override
public void inactivityDetected() {
...your move...
}
});
idleTimer.startIdleTimer();
答案 7 :(得分:3)
即使您可以使用@gfrigon或@AKh解决方案来管理您的要求。
但这里有计时器和处理程序免费解决方案。我已经有了很好的管理计时器解决方案。但我已经成功实现了Timer和Handler免费解决方案。
首先,如果您使用计时器或处理程序,我会告诉您您需要管理的内容。
最后,我实施了一个
的解决方案ACTION_SCREEN_ON
/ ACTION_SCREEN_OFF
广播接收器。 最简单可靠的解决方案
我们不会通过计时器观察用户不活动,而是检查用户活动的最后活动时间。因此,当用户下次交互应用时,我会检查上次交互时间。
以下是BaseActivity.class
,您将从每个活动类而不是LoginActivity
扩展。您将在此课程的字段TIMEOUT_IN_MILLI
中定义退出时间。
import android.content.Intent;
import android.content.SharedPreferences;
import android.support.v7.app.AppCompatActivity;
import android.widget.Toast;
public class BaseActivity extends AppCompatActivity {
public static final long TIMEOUT_IN_MILLI = 1000 * 20;
public static final String PREF_FILE = "App_Pref";
public static final String KEY_SP_LAST_INTERACTION_TIME = "KEY_SP_LAST_INTERACTION_TIME";
@Override
public void onUserInteraction() {
super.onUserInteraction();
if (isValidLogin())
getSharedPreference().edit().putLong(KEY_SP_LAST_INTERACTION_TIME, System.currentTimeMillis()).apply();
else logout();
}
public SharedPreferences getSharedPreference() {
return getSharedPreferences(PREF_FILE, MODE_PRIVATE);
}
public boolean isValidLogin() {
long last_edit_time = getSharedPreference().getLong(KEY_SP_LAST_INTERACTION_TIME, 0);
return last_edit_time == 0 || System.currentTimeMillis() - last_edit_time < TIMEOUT_IN_MILLI;
}
public void logout() {
Intent intent = new Intent(this, LoginActivity.class);
intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TASK | Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(intent);
finish();
Toast.makeText(this, "User logout due to inactivity", Toast.LENGTH_SHORT).show();
getSharedPreference().edit().remove(KEY_SP_LAST_INTERACTION_TIME).apply(); // make shared preference null.
}
}
答案 8 :(得分:2)
在我的搜索过程中,我找到了很多答案,但这是我得到的最佳答案。但是这个代码的限制是它只适用于不适用于整个应用程序的活动。以此为参考。
myHandler = new Handler();
myRunnable = new Runnable() {
@Override
public void run() {
//task to do if user is inactive
}
};
@Override
public void onUserInteraction() {
super.onUserInteraction();
myHandler.removeCallbacks(myRunnable);
myHandler.postDelayed(myRunnable, /*time in milliseconds for user inactivity*/);
}
例如,如果您使用8000,则任务将在用户不活动8秒后完成。
答案 9 :(得分:1)
用户不活动可以使用android中的onUserInteraction()
覆盖方法进行检测
@Override
public void onUserInteraction() {
super.onUserInteraction();
}
这是示例代码, 用户闲置3分钟后退出(HomeActivity-> LoginActivity)
public class HomeActivity extends AppCompatActivity {
private static String TAG = "HomeActivity";
private Handler handler;
private Runnable r;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_home);
handler = new Handler();
r = new Runnable() {
@Override
public void run() {
Intent intent = new Intent(getApplicationContext(), LoginActivity.class);
startActivity(intent);
Log.d(TAG, "Logged out after 3 minutes on inactivity.");
finish();
Toast.makeText(HomeActivity.this, "Logged out after 3 minutes on inactivity.", Toast.LENGTH_SHORT).show();
}
};
startHandler();
}
public void stopHandler() {
handler.removeCallbacks(r);
Log.d("HandlerRun", "stopHandlerMain");
}
public void startHandler() {
handler.postDelayed(r, 3 * 60 * 1000);
Log.d("HandlerRun", "startHandlerMain");
}
@Override
public void onUserInteraction() {
super.onUserInteraction();
stopHandler();
startHandler();
}
@Override
protected void onPause() {
stopHandler();
Log.d("onPause", "onPauseActivity change");
super.onPause();
}
@Override
protected void onResume() {
super.onResume();
startHandler();
Log.d("onResume", "onResume_restartActivity");
}
@Override
protected void onDestroy() {
super.onDestroy();
stopHandler();
Log.d("onDestroy", "onDestroyActivity change");
}
}
答案 10 :(得分:0)
我认为需要将计时器与最后一次激活时间结合起来。
所以这样:
在onCreate(Bundle savedInstanceState)中启动一个计时器,比如5分钟
在onUserInteraction()中只存储当前时间
到目前为止非常简单。
现在,当计时器弹出这样的时候:
答案 11 :(得分:0)
我有类似SO问题的情况,我需要跟踪用户1分钟的不活动状态,然后重定向用户以启动Activity,我还需要清除活动堆栈。
基于@gfrigon答案,我提出了此解决方案。
public abstract class ActionBar extends AppCompatActivity {
public static final long DISCONNECT_TIMEOUT = 60000; // 1 min
private final MyHandler mDisconnectHandler = new MyHandler(this);
private Context mContext;
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mContext = this;
}
/*
|--------------------------------------------------------------------------
| Detect user inactivity in Android
|--------------------------------------------------------------------------
*/
// Static inner class doesn't hold an implicit reference to the outer class
private static class MyHandler extends Handler {
// Using a weak reference means you won't prevent garbage collection
private final WeakReference<ActionBar> myClassWeakReference;
public MyHandler(ActionBar actionBarInstance) {
myClassWeakReference = new WeakReference<ActionBar>(actionBarInstance);
}
@Override
public void handleMessage(Message msg) {
ActionBar actionBar = myClassWeakReference.get();
if (actionBar != null) {
// ...do work here...
}
}
}
private Runnable disconnectCallback = new Runnable() {
@Override
public void run() {
// Perform any required operation on disconnect
Intent startActivity = new Intent(mContext, StartActivity.class);
// Clear activity stack
startActivity.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_CLEAR_TASK);
startActivity(startActivity);
}
};
public void resetDisconnectTimer() {
mDisconnectHandler.removeCallbacks(disconnectCallback);
mDisconnectHandler.postDelayed(disconnectCallback, DISCONNECT_TIMEOUT);
}
public void stopDisconnectTimer() {
mDisconnectHandler.removeCallbacks(disconnectCallback);
}
@Override
public void onUserInteraction(){
resetDisconnectTimer();
}
@Override
public void onResume() {
super.onResume();
resetDisconnectTimer();
}
@Override
public void onStop() {
super.onStop();
stopDisconnectTimer();
}
}
答案 12 :(得分:0)
最好的方法是通过在应用程序calss中注册AppLifecycleCallbacks
来处理整个应用程序(假设您有多个活动)。您可以在Application类中将registerActivityLifecycleCallbacks()
与以下回调一起使用(我建议创建一个AppLifecycleCallbacks类来扩展ActivityLifecycleCallbacks):
public interface ActivityLifecycleCallbacks {
void onActivityCreated(Activity activity, Bundle savedInstanceState);
void onActivityStarted(Activity activity);
void onActivityResumed(Activity activity);
void onActivityPaused(Activity activity);
void onActivityStopped(Activity activity);
void onActivitySaveInstanceState(Activity activity, Bundle outState);
void onActivityDestroyed(Activity activity);
}
答案 13 :(得分:0)
在KOTLIN中处理用户的交互超时:
//Declare handler
private var timeoutHandler: Handler? = null
private var interactionTimeoutRunnable: Runnable? = null
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_aspect_ratio)
//Initialise handler
timeoutHandler = Handler();
interactionTimeoutRunnable = Runnable {
// Handle Timeout stuffs here
}
//start countdown
startHandler()
}
// reset handler on user interaction
override fun onUserInteraction() {
super.onUserInteraction()
resetHandler()
}
//restart countdown
fun reset() {
timeoutHandler!!.removeCallbacks(interactionTimeoutRunnable);
timeoutHandler!!.postDelayed(interactionTimeoutRunnable, 10*1000); //for 10 second
}
// start countdown
fun startHandler() {
timeoutHandler!!.postDelayed(interactionTimeoutRunnable, 10*1000); //for 10 second
}
答案 14 :(得分:0)
我知道我想添加这个答案为时已晚,但是对于所有未来的新观众来说,我已经阅读了上面的大多数代码并尝试了一下。但是他们都没有为我工作。下面给出的代码完全可以满足新查看者的需求。该代码将起作用:
public class MainActivity extends AppCompatActivity {
private Timer timer;
private Toolbar toolbar;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
}
@Override
protected void onPause() {
super.onPause();
timer = new Timer();
Log.i("Main", "Invoking logout timer");
LogOutTimerTask logoutTimeTask = new LogOutTimerTask();
timer.schedule(logoutTimeTask, 300000); //auto logout in 5 minutes
}
@Override
protected void onResume() {
super.onResume();
if (timer != null) {
timer.cancel();
Log.i("Main", "cancel timer");
timer = null;
}
}
private class LogOutTimerTask extends TimerTask {
@Override
public void run() {
//redirect user to login screen
Intent i = new Intent(MainActivity.this, YourActivity.class); //where
you want to load when inactive
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(i);
finish();
}
}
}
答案 15 :(得分:0)
这是一个完整的解决方案,可以处理几分钟(例如3分钟)后的用户不活动状态。 这样可以解决常见的问题,例如,当应用程序在后台超时时,活动会跳到前台。
首先,我们创建一个BaseActivity,所有其他Activity都可以扩展。
这是BaseActivity代码。
package com.example.timeout;
import android.app.Activity;
import android.app.Dialog;
import android.content.Context;
import android.content.Intent;
import android.os.Bundle;
import android.text.TextUtils;
import android.view.View;
import android.view.Window;
import android.widget.TextView;
import androidx.appcompat.app.AppCompatActivity;
import javax.annotation.Nullable;
public class BaseActivity extends AppCompatActivity implements LogoutListener {
private Boolean isUserTimedOut = false;
private static Dialog mDialog;
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
((TimeOutApp) getApplication()).registerSessionListener(this);
((TimeOutApp) getApplication()).startUserSession();
}
@Override
public void onUserInteraction() {
super.onUserInteraction();
}
@Override
protected void onResume() {
super.onResume();
if (isUserTimedOut) {
//show TimerOut dialog
showTimedOutWindow("Time Out!", this);
} else {
((TimeOutApp) getApplication()).onUserInteracted();
}
}
@Override
public void onSessionLogout() {
isUserTimedOut = true;
}
public void showTimedOutWindow(String message, Context context) {
if (mDialog != null) {
mDialog.dismiss();
}
mDialog = new Dialog(context);
mDialog.requestWindowFeature(Window.FEATURE_NO_TITLE);
mDialog.setContentView(R.layout.dialog_window);
mDialog.setCancelable(false);
mDialog.setCanceledOnTouchOutside(false);
TextView mOkButton = (TextView) mDialog.findViewById(R.id.text_ok);
TextView text_msg = (TextView) mDialog.findViewById(R.id.text_msg);
if (message != null && (!TextUtils.isEmpty(message)) && (!message.equalsIgnoreCase("null"))) {
text_msg.setText(message);
}
mOkButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (mDialog != null){
mDialog.dismiss();
Intent intent = new Intent(BaseActivity.this, LoginActivity.class);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_CLEAR_TASK);
startActivity(intent);
finish();
}
}
});
if(!((Activity) context).isFinishing())
{
//show dialog
mDialog.show();
}
}
}
接下来,我们为“注销监听器”创建一个接口
package com.example.timeout;
public interface LogoutListener {
void onSessionLogout();
}
最后,我们创建一个扩展“应用程序”的Java类
package com.example.timeout;
import android.app.Application;
import java.util.Timer;
import java.util.TimerTask;
public class TimeOutApp extends Application {
private LogoutListener listener;
private Timer timer;
private static final long INACTIVE_TIMEOUT = 180000; // 3 min
public void startUserSession () {
cancelTimer ();
timer = new Timer ();
timer.schedule(new TimerTask() {
@Override
public void run() {
listener.onSessionLogout ();
}
}, INACTIVE_TIMEOUT);
}
private void cancelTimer () {
if (timer !=null) timer.cancel();
}
public void registerSessionListener(LogoutListener listener){
this.listener = listener;
}
public void onUserInteracted () {
startUserSession();
}
}
注意:不要忘记在清单文件中的应用程序标签中添加“ TimeOutApp”类
<application
android:name=".TimeOutApp">
</application>
答案 16 :(得分:0)
open class SubActivity : AppCompatActivity() {
var myRunnable:Runnable
private var myHandler = Handler()
init {
myRunnable = Runnable{
toast("time out")
var intent = Intent(this, MainActivity::class.java)
startActivity(intent)
}
}
fun toast(text: String) {
runOnUiThread {
val toast = Toast.makeText(applicationContext, text, Toast.LENGTH_SHORT)
toast.show()
}
}
override fun onUserInteraction() {
super.onUserInteraction();
myHandler.removeCallbacks(myRunnable)
myHandler.postDelayed(myRunnable, 3000)
}
override fun onPause() {
super.onPause()
myHandler.removeCallbacks(myRunnable)
}
override fun onResume() {
super.onResume()
myHandler.postDelayed(myRunnable, 3000)
}
}
扩展您的活动
YourActivity:SubActivity(){}
在YourActivity上经过3000毫秒后用户不活动时,进入MainActivity
我使用了先前的答案,并将其转换为kotlin。