使用python中的selenium webdriver查找具有显式等待的元素

时间:2014-09-15 14:50:32

标签: python python-2.7 selenium selenium-webdriver

我正在尝试使用链接文本找到元素,我正在使用以下代码

handle = driver.window_handles
#handle for windows
driver.switch_to.window(handle[1])
#switching to new window
link = wait.until(EC.presence_of_element_located((By.LINK_TEXT, "Followers ")))

我正在追踪追溯

Traceback (most recent call last):
File "<pyshell#28>", line 1, in <module>
link = wait.until(EC.presence_of_element_located((By.LINK_TEXT, "Followers ")))
File "C:\Python27\lib\site-packages\selenium\webdriver\support\wait.py", line 71, in until
raise TimeoutException(message)
TimeoutException: Message: ''

我想要选择的元素的HTML是

<a href="/Kevin-Rose/followers">Followers <span class="profile_count">43,799</span></a>

我该如何解决这个问题?

2 个答案:

答案 0 :(得分:4)

如果您使用By.LINK_TEXT,则应该有一个完全相同的文字链接:Followers,但您有Followers 43,799

在您的情况下,您应该使用By.PARTIAL_LINK_TEXT代替:

wait.until(EC.presence_of_element_located((By.PARTIAL_LINK_TEXT, 'Followers')))

更新以下是工作示例:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

driver = webdriver.Chrome()  # CHANGEME
driver.get('http://www.quora.com/Kevin-Rose')
element = WebDriverWait(driver, 2).until(
    EC.presence_of_element_located((By.PARTIAL_LINK_TEXT, "Followers"))
)
element.click()

答案 1 :(得分:0)

欢呼

from selenium import webdrivercode
from selenium.webdriver.common.by import By
import selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

driver = webdriver.Chrome(ChromeDriverManager().install())
driver.get("http://somedomain/url_that_delays_loading")

#Follow below syntax
element = WebDriverWait(driver, 10)
element.until(EC.presence_of_element_located((By.ID, '--webElement--')))