Question

我根据数据库的位置ID和数量检索数据超过五项，但我想要特定的位置ID检索数量超过0项的项目

这是我的疑问：

SELECT DISTINCT(warehouses.item_id), SUM(warehouses.qty) AS qty, items.gender_id, items_dept.desc, items_dept.dept_id, items.msrp,items.rtp
FROM `warehouses`
    JOIN `items`
        ON items.item_id = warehouses.item_id
    JOIN `items_dept`
        ON items_dept.dept_id = items.dept_id
WHERE items.gender_id IN (3,5,6)
AND qty > 5
AND warehouses.wrhs_id IN (20,21,22,23,24,25,26,27,28,29,30,31,32,38,40,44,47,49,55,60,61)
AND items.dept_id = :catId
AND items.rtp BETWEEN :priceX AND :priceY
GROUP BY warehouses.item_id
ORDER BY warehouses.item_id ASC

我想要wrhs_id（44）数量不超过5但超过0

Answer 1

在SQL中，您可以使用LIMIT参数指定返回项的限制，但如果检索0项则表示您输入了错误或数据库中没有数据

Answer 2

试试这个：

SELECT DISTINCT(warehouses.item_id), SUM(warehouses.qty) AS qty, items.gender_id, items_dept.desc,items_dept.dept_id,items.msrp,items.rtp
            FROM `warehouses`
            JOIN `items`      ON items.item_id      = warehouses.item_id
            JOIN `items_dept` ON items_dept.dept_id = items.dept_id
            WHERE items.gender_id IN (3,5,6)
            AND qty > 0
            AND warehouses.wrhs_id = 44
            AND items.dept_id = :catId
            AND items.rtp BETWEEN :priceX AND :priceY
            GROUP BY warehouses.item_id
            ORDER BY warehouses.item_id ASC

Answer 3

SELECT DISTINCT(warehouses.item_id), SUM(warehouses.qty) AS qty, items.gender_id, items_dept.desc, items_dept.dept_id, items.msrp,items.rtp
FROM `warehouses`
    JOIN `items`
        ON items.item_id = warehouses.item_id
    JOIN `items_dept`
        ON items_dept.dept_id = items.dept_id
WHERE items.gender_id IN (3,5,6)
AND ((
        qty > 5
        AND
        warehouses.wrhs_id IN (20,21,22,23,24,25,26,27,28,29,30,31,32,38,40,47,49,55,60,61)
    )
    OR (
        qty > 0
        AND
        warehouses.wrhs_id = 44
    )
)
AND items.dept_id = :catId
AND items.rtp BETWEEN :priceX AND :priceY
GROUP BY warehouses.item_id
ORDER BY warehouses.item_id ASC

SQL查询从数据库中检索数据

3 个答案: