从数据库检索Json数据

Question

我有一个数据库，将座位号存储在单列中。如何从给定数据中以json格式检索这些座位号，这些数据作为参数$ tripIdNo，$ fleetRegNo，$ newSeats发送... 我已经尝试过了，但是没有成功

private function checkBooking($tripIdNo = null, $fleetRegNo = null, $newSeats = null)
    {
        //---------------fleet seats----------------
        $fleetSeats = $this->db->select("
                total_seat, seat_numbers, fleet_facilities
            ")->from("fleet_registration")
            ->where('reg_no', $fleetRegNo)
            ->get()
            ->row();

        $seatArray = array();
        $seatArray = array_map('trim', explode(',', $fleetSeats->seat_numbers));

        //-----------------booked seats-------------------
        $bookedSeats = $this->db->select("
                tb.trip_id_no,
                SUM(tb.total_seat) AS booked_seats, 
                GROUP_CONCAT(tb.seat_numbers SEPARATOR ', ') AS booked_serial 
            ")
            ->from('tkt_booking AS tb')
            ->where('tb.trip_id_no', $tripIdNo)
            ->group_start()
                ->where("tb.tkt_refund_id IS NULL", null, false)
                ->or_where("tb.tkt_refund_id", 0)
                ->or_where("tb.tkt_refund_id", null)
            ->group_end()
            ->get()
            ->row();

        $bookArray = array();
        $bookArray = array_map('trim', explode(',', $bookedSeats->booked_serial));


        //-----------------booked seats-------------------
        $newSeatArray = array();
        $newSeatArray = array_map('trim', explode(',', $newSeats));

        if (sizeof($newSeatArray) > 0) {

            foreach ($newSeatArray as $seat) {

                if (!empty($seat)) {
                    if (in_array($seat, $bookArray)) {
                        return false; 
                    } else if (!in_array($seat, $seatArray)) {
                        return false; 
                    }    
                     } 

            }  
            return true;
        } else {
            return false;
        } 
    }

我已经附上了数据库的图像。从那两个表中，分别是trip_booking和Fleet_registration。关于此问题的任何建议。