我创建了不同的视图,因为我希望以5个步骤显示html表单。
这个功能是showStep(x)
。由于我添加了函数showCameraUpload()
和showContactData()
,如果我点击“Step2”,“Step3”等等,没有任何反应......它之前完美无缺,如果我放置函数我只是想在一个新的脚本中实现它们运行良好。
我收到以下两个错误:
未捕获的SyntaxError:意外的令牌ILLEGAL
未捕获的ReferenceError:未定义show_step
我做错了什么?
使用Javascript:
<script>
function show_step(x) {
switch (x) {
case 1:
document.getElementById('step_content_1').style.display = "block";
document.getElementById('step_content_2').style.display = "none";
document.getElementById('step_content_3').style.display = "none";
document.getElementById('step_content_4').style.display = "none";
document.getElementById('step_content_5').style.display = "none";
$('#step_nav_pill_1').addClass('active');
$('#step_nav_pill_2').removeClass('active');
$('#step_nav_pill_3').removeClass('active');
$('#step_nav_pill_4').removeClass('active');
$('#step_nav_pill_5').removeClass('active');
break;
case 2:
document.getElementById('step_content_1').style.display = "none";
document.getElementById('step_content_2').style.display = "block";
document.getElementById('step_content_3').style.display = "none";
document.getElementById('step_content_4').style.display = "none";
document.getElementById('step_content_5').style.display = "none";
$('#step_nav_pill_1').removeClass('active');
$('#step_nav_pill_2').addClass('active');
$('#step_nav_pill_3').removeClass('active');
$('#step_nav_pill_4').removeClass('active');
$('#step_nav_pill_5').removeClass('active');
break;
case 3:
document.getElementById('step_content_1').style.display = "none";
document.getElementById('step_content_2').style.display = "none";
document.getElementById('step_content_3').style.display = "block";
document.getElementById('step_content_4').style.display = "none";
document.getElementById('step_content_5').style.display = "none";
$('#step_nav_pill_1').removeClass('active');
$('#step_nav_pill_2').removeClass('active');
$('#step_nav_pill_3').addClass('active');
$('#step_nav_pill_4').removeClass('active');
$('#step_nav_pill_5').removeClass('active');
break;
case 4:
document.getElementById('step_content_1').style.display = "none";
document.getElementById('step_content_2').style.display = "none";
document.getElementById('step_content_3').style.display = "none";
document.getElementById('step_content_4').style.display = "block";
document.getElementById('step_content_5').style.display = "none";
$('#step_nav_pill_1').removeClass('active');
$('#step_nav_pill_2').removeClass('active');
$('#step_nav_pill_3').removeClass('active');
$('#step_nav_pill_4').addClass('active');
$('#step_nav_pill_5').removeClass('active');
break;
case 5:
document.getElementById('step_content_1').style.display = "none";
document.getElementById('step_content_2').style.display = "none";
document.getElementById('step_content_3').style.display = "none";
document.getElementById('step_content_4').style.display = "none";
document.getElementById('step_content_5').style.display = "block";
$('#step_nav_pill_1').removeClass('active');
$('#step_nav_pill_2').removeClass('active');
$('#step_nav_pill_3').removeClass('active');
$('#step_nav_pill_4').removeClass('active');
$('#step_nav_pill_5').addClass('active');
break;
}
}
function showCameraUpload(){
document.getElementById('step_content_2').style.display = "block";
document.getElementById('camera_upload').style.display = "block";
document.getElementById('contact_data').style.display = "none";
$('#camera_li').addClass('active');
$('#contact_li').removeClass('active');
}
function showContactData(){
document.getElementById('step_content_2').style.display = "block";
document.getElementById('contact_data').style.display = "block";
document.getElementById('camera_upload').style.display = "none";#
$('#contact_li').addClass('active');
$('#camera_li').removeClass('active');
}
</script>
答案 0 :(得分:0)
我不确定这是否是复制和粘贴错误,但看起来你有一个奇怪的回显线'
function fadeOut() {
echo'<script>
$("p").fadeOut(3000)
}
取而代之的是删除回声:
function fadeOut() {
//echo'<script> <!-- not sure what is going on here
$("p").fadeOut(3000)
}
另外看看
document.getElementById('camera_upload').style.display = "none";#
应该是
document.getElementById('camera_upload').style.display = "none";
看看google chrome dev工具,javascript控制台可以帮助你找到未来的错误。