Question

请求哟帮助分页链接。在我的数据库中，我有3条记录，我想在每页显示单条记录。当我选择下一个分页链接数时，数据没有被提取。当我点击分页链接的第2个时，echo var_dump（）显示Result为空，我没有获得echo $ data-＆gt的任何值;电子邮件。但是当我第一次搜索我能够显示单个记录时，问题只出现在下一个分页链接那么可能是什么错误？我无法得到答案，而且我不确定会发生什么，所以我在下面发布我的代码请仔细阅读并帮助我。请求你帮助我。

**HERE STARTS MY CONTROLLER**

 public function users($limit=1,$offset = 0)
{
$this->load->helper('url');
$data = array();
$look = $this->input->post('look');
$age = $this->input->post('age');
$age_from = $this->input->post('age_from');
$age_to = $this->input->post('age_to');
$se_ct = $this->input->post('sect');
$subsect = $this->input->post('subsect');
$coun_try = $this->input->post('country');
$sta_te = $this->input->post('state');
$ci_ty = $this->input->post('city');
$qualification = $this->input->post('qualification');
$results = $this->searchresultss->login($look, $age, $age_to, $age_from, $se_ct, $subsect, $coun_try, $sta_te, $ci_ty, $qualification);
$this->load->helper('url');
$config = array();
$config['base_url'] = base_url().'searchresult/users';
$config['total_rows'] = count($results);
$config['per_page'] = $limit;
$this->load->library('pagination', $config);
$data['pagination_links'] = $this->pagination->create_links();
$data['results'] = array_slice($results, $offset, $limit);
 $this->load->view('searchresult', $data);
$this->load->view('includes/khelp');
$this->load->view('includes/kfooter');


**HERE STARTS MY MODEL PAGE**

     Class Searchresultss extends CI_Model
            {

            public function login($look, $age, $age_to, $age_from, $se_ct, $subsect, $coun_try, $sta_te, $ci_ty, $qualification)
            {

                    return $this->db->query("SELECT *
                    FROM users
                    WHERE   gender = '$look'
                    And status='1'")->result();

             }

            }


**HERE START MY VIEW PAGE**
echo var_dump($_POST);
if (empty($results)) {
 echo 'Results set is empty';
        } else 
        {
        foreach ($results as $data) {
                echo $data->email.'<br />';
            }

        }
        echo $pagination_links;

Answer 1

问题在于分页链接不包括POST变量（以及通过GET请求超链接的事实）。我建议你在$ _GET和$ _POST上做一个var_dump（），问题就会变得更加明显。

可能的解决方案是将post变量包含为url参数。例如，

$config['base_url'] = base_url().'searchresult/users/look_param/age_param/etcetc';

但是，您需要添加处理上述内容的功能。

当我选择链接时，codeigniter分页链接不起作用

1 个答案: