Question

可能这个问题真的很愚蠢，但我尝试了很多东西而且我总是得到同样的错误......

正如您所看到的，我尝试在CodeIgniter中使用Pagination，我可以使用页面和链接加载视图，但是当我点击链接时，它会显示＆＃34;找不到对象！＆＃34;

这是我的控制器：

class Controller extends CI_Controller {

    public function __construct() {
        parent:: __construct();
        $this->load->helper("url");
        $this->load->model("Blogs_model");
        $this->load->library("pagination");
    }

    public function index() {
        $config = array();
        $config["base_url"] = base_url() . "pagination/";
        $config["total_rows"] = $this->Blogs_model->record_count();
        $config["per_page"] = 2;
        $config["uri_segment"] = 3;
        $config['first_link'] = 'First';
        $config['last_link'] = 'End';
        $config['next_link'] = 'Next &rarr;';
        $config['prev_link'] = '&larr; Prev';

        $this->pagination->initialize($config);

        $page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0;
        $data["results"] = $this->Blogs_model->fetch_entries($config["per_page"], $page);
        $data["links"] = $this->pagination->create_links();

        $this->load->view("example1", $data);
    }
}

routes.php文件：

route['default_controller'] = "controller";
$route['pagination/(:any)'] = 'pagination';
$route['404_override'] = '';

的config.php：

config['base_url']  = 'http://localhost/ci';

有人可以帮帮我吗？谢谢。

修改多数民众赞成我的模特：

class Blogs_model extends CI_Model {

    public function __construct() {
        parent::__construct();
    }

    public function record_count() {
        return $this->db->count_all("entry");
    }

    public function fetch_entries($limit, $start) {
        $this->db->limit($limit, $start);
        $query = $this->db->get("entry");

        if ($query->num_rows() > 0) {
            foreach ($query->result() as $row) {
                $data[] = $row;
            }
            return $data;
        }
        return false;
    }
}

问题是当我加载页面时：localhost / ci /它工作正常，但是当我点击链接时，url会更改为localhost / ci / pagination / 2并且不起作用。我想这是路线的问题，但无论如何我不确定。

编辑2 感谢所有评论家伙，最后我设法让它工作，但Index.php活跃，我的意思是我的网址现在是：

http://localhost/ci/index.php/controller/index/2

我想让它在没有index.php的情况下运行。我的代码现在是这样的：控制器：

class Controller extends CI_Controller {

    public function __construct() {
        parent:: __construct();
        $this->load->helper("url");
        $this->load->model("Blogs_model");
        $this->load->library("pagination");
    }

    public function index() {
        $config = array();
        $config["base_url"] = "http://localhost/ci/index.php/controller/index";
        $config["total_rows"] = $this->Blogs_model->record_count();
        $config["per_page"] = 2;

        $this->pagination->initialize($config);

        $data["results"] = $this->Blogs_model->fetch_entries($config["per_page"], $this->uri->segment(3));
        $data["links"] = $this->pagination->create_links();

        $this->load->view("example1", $data);
    }
}

config.php中的base_url是

http://localhost/ci;

此外，路线文件现在只有：

$route['default_controller'] = "controller";
$route['404_override'] = '';

Answer 1

应该看起来像这样：

路线档案：

$route['blog/(:num)'] = "controller/index/$1";
$route['blog'] = "controller/index";

控制器：

public function index($page = 0) {
  $news = $this->blog_model->get_blog($page);
}

型号：

public function get_blog($page) {
  $offset = $page * 2;
  $stuff = $this->db->get('articles', $offset, 2);
}

Answer 2

而不是：

$page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0;
$data["results"] = $this->Blogs_model->fetch_entries($config["per_page"], $page);

试试这个：

$page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0;
$offset = $page==0? 0: ($page-1)*$config["per_page"];
$data["results"] = $this->Blogs_model->fetch_entries($config["per_page"], $offset);

除非你的模型正在做这项工作，否则你需要传递偏移而不是页面。

单击链接时CodeIgniter分页不起作用

2 个答案: