Question

#include <iostream>
using namespace std;

class Cube
{
    int w,l,d;
public:
    Cube(int w, int l, int d) : w(w), l(l), d(d){}
    int getWidth() const {return w;}
    int getLength() const {return l;}
    int getDepth() const {return d;}
};

ostream& operator<< (ostream&os, const Cube& c)
{
    os << "( " << c.getWidth() << ", " << c.getLength() << ", " << c.getDepth() << ")";
    return os;
}

Cube operator+ (Cube& c1, Cube& c2)
{
    int n = c1.getWidth() * c1.getDepth() * c1.getLength();
    int d = c2.getWidth() * c2.getDepth() * c2.getLength();
    int t = n + d;
    return Cube(t);
}

int main()
{
    Cube c1(3,5,9), c2(2,1,4);
    cout << c1 << endl;
    cout << c2 << endl;
    cout << "Total Volume: " << c1 + c2;
}

在我的算子+中有一些我无法找到的错误。运算符重载（+）应该加上两个立方体，这将导致两个立方体的体积相加。

我应该怎样对我的运算符重载（+）？

Answer 1

如果你想用operator +得到两个立方体的总体积，你应该返回int而不是Cube对象，你无论如何也不可能使用Cube和Cube。你可以这样做

int operator+ (Cube& c1, Cube& c2) {
    int n = c1.getWidth() * c1.getDepth() * c1.getLength();
    int d = c2.getWidth() * c2.getDepth() * c2.getLength();
    return n + d; 
}

运算符重载为+

1 个答案: