我有以下程序,其中我使用AES_CBC加密和解密给定文本,密钥长度为256位。我想知道为什么当plaintext
,ciphertext
和checktext
不是全局变量时,我在标题中出现错误,并且当它们正常时可以正常工作。谢谢!
#include <stdio.h>
#include <openssl\aes.h>
#include <openssl\rand.h>
#include <conio.h>
#include <openssl\des.h>
#define BIG_TEST_SIZE 1024
char plaintext[BIG_TEST_SIZE];
char ciphertext[BIG_TEST_SIZE];
char checktext[BIG_TEST_SIZE];
AES_KEY key;
char rkey[32+1];
static void hexdump(FILE *f,const char *title,const unsigned char *s,int l)
{
int n=0;
fprintf(f,"%s",title);
for( ; n < l ; ++n)
{
if((n%16) == 0)
fprintf(f,"\n%04x",n);
fprintf(f," %02x",s[n]);
}
fprintf(f,"\n");
}
int main(int argc, char* argv[])
{
//char plaintext[BIG_TEST_SIZE];
//char ciphertext[BIG_TEST_SIZE];
//char checktext[BIG_TEST_SIZE];
char saved_iv[32+1];
int err = 0;
RAND_pseudo_bytes((unsigned char*)rkey, sizeof rkey);
unsigned char iv[32+1]="01234567890123456789012345678901";
memcpy(saved_iv, iv, sizeof saved_iv);
strcpy((char*)plaintext,"aaa");
const size_t encslength = ((strlen(plaintext) + AES_BLOCK_SIZE) / AES_BLOCK_SIZE) * AES_BLOCK_SIZE;
// Straight encrypt
AES_set_encrypt_key((unsigned char*)rkey, 256, &key);
hexdump(stdout, "plaintext", (unsigned char*)plaintext, strlen(plaintext));
AES_cbc_encrypt((unsigned char*)plaintext, (unsigned char*)ciphertext, encslength, &key, (unsigned char*)iv,AES_ENCRYPT);
hexdump(stdout, "ciphertext", (unsigned char*)ciphertext, strlen(plaintext));
// Straight decrypt
AES_set_decrypt_key((unsigned char*)rkey, 256, &key);
memcpy(iv, saved_iv, sizeof iv);
AES_cbc_encrypt((unsigned char*)ciphertext, (unsigned char*)checktext, encslength, &key, (unsigned char*)iv,AES_DECRYPT);
hexdump(stdout, "checktext", (unsigned char*)checktext, strlen(plaintext));
getch();
}
答案 0 :(得分:1)
全局和静态变量初始化为零,而局部变量不是。 因此,当您在本地定义明文,密文和 checktext 时,请使用memset将其初始化为零。 你的字符串应该是空终止,但在你的情况下它不是。 密文, checktext 未终止。由于 strcpy 调用,明文变为空终止。