按照此问题Keyboard Interrupts with python's multiprocessing Pool中的一些建议,编写名为test.py的测试代码
from multiprocessing import Pool
from multiprocessing.pool import IMapIterator
import fileinput
def wrapper(func):
def wrap(self, timeout=None):
# Note: the timeout of 1 googol seconds introduces a rather subtle
# bug for Python scripts intended to run many times the age of the universe.
return func(self, timeout=timeout if timeout is not None else 1e100)
return wrap
IMapIterator.next = wrapper(IMapIterator.next)
def main():
p = Pool(1)
try:
for _ in p.imap(worker, fileinput.input(), 1):
pass
except KeyboardInterrupt:
p.terminate()
def worker(line):
print line
if __name__ == '__main__':
main()
当我在终端中运行python test.py时:
python test.py
我仍然有KeyboardInterrupt回溯,而且我必须发送Ctrl ^ C两次才能停止脚本。我如何处理KeyboardInterrupt并让它不打印tarceback并只使用一次Ctrl ^ c来优雅地停止它。
^CProcess PoolWorker-1:
Traceback (most recent call last):
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/multiprocessing/process.py", line 258, in _bootstrap
self.run()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/multiprocessing/process.py", line 114, in run
self._target(*self._args, **self._kwargs)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/multiprocessing/pool.py", line 102, in worker
task = get()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/multiprocessing/queues.py", line 376, in get
return recv()
KeyboardInterrupt
^CTraceback (most recent call last):
File "test.py", line 27, in <module>
main()
File "test.py", line 21, in main
p.terminate()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/multiprocessing/pool.py", line 452, in terminate
self._worker_handler._state = TERMINATE
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/multiprocessing/util.py", line 201, in __call__
res = self._callback(*self._args, **self._kwargs)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/multiprocessing/pool.py", line 504, in _terminate_pool
if threading.current_thread() is not task_handler:
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 958, in join
self.__block.wait(delay)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 358, in wait
_sleep(delay)
KeyboardInterrupt
答案 0 :(得分:3)
查看标准库中包含的信号模块。您可以在主进程中注册信号处理程序
from signal import *
def siginthndlr(sig, frame):
'''do what you need here'''
print "Keyboard interrupt catched"
signal(SIGINT, siginthndlr) #Register SIGINT handler function
这将优雅地杀死工作进程而不是杀死主进程。