Question

在我的项目中，我有一个NSMutableArray * arrayMatchs，其中字典作为对象。在这本词典中，我有一个Key，字符串作为值，在数组中的字典之间重合。有一种方法可以创建一个内部数组的新数组作为填充了具有相同键/值的字典的对象吗？

在我的第一个数组（arrayMatchs）下面：

arrayMatchs (
    {
    "match_commentary_available" = facup;
    "match_comp_id" = 1198;   <------------------------
    "match_date" = "Sep 09";
    "match_et_score" = "";
    "match_formatted_date" = "09.09.2014";
    "match_ft_score" = "";
    "match_ht_score" = "";
    "match_id" = 1937555;
    "match_localteam_id" = 19941;
    "match_localteam_name" = "Hartley Wintney";
    "match_localteam_score" = "?";
    "match_season_beta" = "";
    "match_static_id" = 1844143;
    "match_status" = "18:30";
    "match_time" = "18:30";
    "match_timer" = "";
    "match_venue_beta" = "";
    "match_venue_city_beta" = "";
    "match_venue_id_beta" = 0;
    "match_visitorteam_id" = 20839;
    "match_visitorteam_name" = Ardley;
    "match_visitorteam_score" = "?";
    "match_week_beta" = "";
},
    {
    "match_commentary_available" = "spain_cup";
    "match_comp_id" = 1397;   <-------------------------------
    "match_date" = "Sep 09";
    "match_et_score" = "";
    "match_formatted_date" = "09.09.2014";
    "match_ft_score" = "";
    "match_ht_score" = "";
    "match_id" = 1909702;
    "match_localteam_id" = 16021;
    "match_localteam_name" = Girona;
    "match_localteam_score" = "?";
    "match_season_beta" = "";
    "match_static_id" = 1845426;
    "match_status" = "18:00";
    "match_time" = "18:00";
    "match_timer" = "";
    "match_venue_beta" = "";
    "match_venue_city_beta" = "";
    "match_venue_id_beta" = 0;
    "match_visitorteam_id" = 16184;
    "match_visitorteam_name" = Tenerife;
    "match_visitorteam_score" = "?";
    "match_week_beta" = "";
},
    {
    "match_commentary_available" = "spain_cup";
    "match_comp_id" = 1397;  <--------------------------------
    "match_date" = "Sep 09";
    "match_et_score" = "";
    "match_formatted_date" = "09.09.2014";
    "match_ft_score" = "";
    "match_ht_score" = "";
    "match_id" = 1909694;
    "match_localteam_id" = 15997;
    "match_localteam_name" = Alaves;
    "match_localteam_score" = "?";
    "match_season_beta" = "";
    "match_static_id" = 1845427;
    "match_status" = "20:00";
    "match_time" = "20:00";
    "match_timer" = "";
    "match_venue_beta" = "";
    "match_venue_city_beta" = "";
    "match_venue_id_beta" = 0;
    "match_visitorteam_id" = 16079;
    "match_visitorteam_name" = Osasuna;
    "match_visitorteam_score" = "?";
    "match_week_beta" = "";
}

）

我需要填充UITableView的新数组应该由数组组成，在特定情况下，第一个对象有一个字典，第二个对象有两个字典。

此时段数= newArray计数

section中的行数= [index：section的newArray对象] count

我希望一切都清楚，并感谢所有的帮助

Alex1982

Answer 1

它不高效或漂亮，但我们的想法是循环你的阵列，随时建立一个新阵列。对于原始文件中的每个项目，您想知道新数组中是否已存在包含该ID的数组。如果是，请将其添加到那里。如果没有，则将其（在新的可变数组中）添加到答案中。像这样......

NSMutableArray *groupedArray = [NSMutableArray array];

for (NSDictionary *d in arrayMatchs) {
    // see if there's a mathing dictionary in the new array
    NSMutableArray *matchingInnerArray;
    for (NSMutableArray *innerArray in groupedArray) {
        NSDictionary *firstDictionary = innerArray[0];
        NSNumber *innerId = firstDictionary[@"match_comp_id"];
        if ([innerId isEqualToNumber:d[@"match_comp_id"]]) {
            matchingInnerArray = innerArray;
            break;
        }
    }
    if (!matchingInnerArray) {
        matchingInnerArray = [NSMutableArray array];
        [groupedArray addObject:matchingInnerArray];
    }
    [matchingInnerArray addObject:d];
}

NSLog(@"%@", groupedArray);

NSMictionary与NSDictionary具有相同的值，用于键入新数组

1 个答案: