Question

有很多像这样的问题，我也有json格式的经验，但我无法解析下面的响应（在底部）：

我正在使用NSJSONSerialization将响应解析为NSDictionary，但是它给出了如下错误：

我的代码：

     NSString *subURL= sharedDa.ip;
        NSData *data=[NSData dataWithContentsOfURL:[NSURL URLWithString:[NSString stringWithFormat:@"http://192.168.69.230/tsadmin.php?tssearch=%@", subURL]]];

        NSError *error=nil;
        NSDictionary* portsResult=[NSJSONSerialization JSONObjectWithData:data options:
                              NSJSONReadingMutableContainers error:&error];
  NSDictionary * tempPorts;
    NSString *k;

        for(k in [portsResult allKeys]){
            tempPorts = [portsResult objectForKey:k];
            NSLog(@"Temporary ports: %@", tempPorts);
        }

错误代码如下：

2012-09-28 18:47:37.508 BNTPRO ST Manager[2609:fb03] -[__NSArrayM allKeys]: unrecognized selector sent to instance 0x6b83ed0
2012-09-28 18:47:37.511 BNTPRO ST Manager[2609:fb03] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[__NSArrayM allKeys]: unrecognized selector sent to instance 0x6b83ed0'
*** First throw call stack:
(0x1568022 0x1b20cd6 0x1569cbd 0x14ceed0 0x14cecb2 0x57cd 0x28fa1e 0x28fd11 0x2a18fd 0x2a1aef 0x2a1dbb 0x2a285f 0x2a2e06 0x2a2a24 0x3e59 0x2595c5 0x2597fa 0xaee85d 0x153c936 0x153c3d7 0x149f790 0x149ed84 0x149ec9b 0x245a7d8 0x245a88a 0x1c8626 0x26d2 0x2645 0x1)
terminate called throwing an exception(lldb)

现在我的数据片段是：[{"k1":{"v":"0"}},{"k2":{"v":"0"}},{"k3":{"v":"0"}},{"k4":{"v":"0"}},{"k5":{"v":"0"}},{"k6":{"v":"0"}},{"k7":{"v":"1"}},{"k8":{"v":"0"}},{"k9":{"v":"1"}},{"k10":{"v":"0"}},{"k11":{"v":"1"}},{"k12":{"v":"0"}},{"k13":{"v":"1"}},{"k14":{"v":"0"}},{"k15":{"v":"0"}},{"k16":{"v":"0"}}] 但它仍然给出相同的错误..即使我deciare iVar作为NSDictionary为什么它抱怨nsmutable数组？

Answer 1

您正在解析的JSON是数组，而不是对象。因此[NSJSONSerialization JSONObjectWithData...]的结果不是NSDictionary *，而是NSArray *。

例如，对于JSON数据

[{"k1":{"v":"0"}}, {"k2":{"v":"0"}}]

你可以使用与此代码类似的东西（现在没有xcode来尝试运行它）：

NSArray * arr = [NSJSONSerialization JSONObjectWithData:data options:...];
int i;
for (i = 0; i < [arr count]; i++) {
    NSDictionary * dic = [arr objectAtIndex:i];
    NSString * k;
    for (k in [dic allKeys]) {
        NSLog(@"Temporary ports: %@", [dic objectForKey:k]);
    }
}

如何将此JSON响应解析为密钥和＆amp;值对数组

1 个答案: