Question

我使用php编程为Leave Management项目从MySQL数据库生成报告。

// mysql query to fetch the report

SELECT * FROM vrv_intranet_leaverequest 
                   WHERE 
                   ((fromdate >='2014-03-10' and fromdate <='2014-03-20')
                   || 
                   (todate >='2014-03-10' and todate <='2014-03-20'))

我从此查询中获得了10个订单项

Id Name   01/03  02/03 03/04 04/04 05/05 
25 Suresh   L     P      P     P   P     
25 Suresh   P     L      P     P   P
28 Balaji   L     L      P     P   P
29 Kumar    P     P      L     L   P
30 Sri      P     L      P     P   P
31 Ganesh   L     L      P     P   P
45 Alex     P     P      P     L   L

获得第25个ID是两次在表中，因为在我的数据库中我有记录。但我想在单行显示在前面。

第25个id在第1和第2个离开，所以它显示为两个记录。但我希望在单个记录中看起来像下面这样：

Id Name   01/03  02/03 03/04 04/04 05/05 
25 Suresh   L     L      P     P   P

Answer 1

使用GROUP BY收集具有相同ID的所有行，并使用MIN()选择每列中的最小值：

SELECT Id, Name, 
        MIN(`01/03`) AS `01/03`, 
        MIN(`02/03`) AS `02/03`,
        MIN(`03/04`) AS `03/04`, 
        MIN(`04/04`) AS `04/04`, 
        MIN(`05/05`) AS `05/05`
FROM vrv_intranet_leaverequest
WHERE ((fromdate >='2014-03-10' and fromdate <='2014-03-20')
        || 
       (todate >='2014-03-10' and todate <='2014-03-20'))
GROUP BY Id

Answer 2

我假设Id是主键

SELECT * FROM vrv_intranet_leaverequest WHERE 
 ((fromdate >='2014-03-10' and fromdate <='2014-03-20') || 
 (todate >='2014-03-10' and todate <='2014-03-20')) GROUP BY Id

php while循环在单个表描述中更新相同的值

2 个答案: