Question

这是我的代码

<?php

    $query= "SELECT album_name FROM gallery group by album_name order by MIN(date_time)";
     $stmt = $connection->prepare($query);
     $stmt->execute();
     $result=$stmt->get_result();
           while ($row = $result->fetch_array(MYSQLI_BOTH)) { //First while loop
           $album_names =htmlspecialchars($row['album_name']);` 
    ?>
      <ul>
        <li data-tags="<?php echo $album_names ?>">

直到这一点，一切正常，它显示了我的数据库中所有相册的名称。我接下来要做的是我希望它显示属于$album_names的所有图片所以我在上面的代码之后编写了这段代码

// Code continues
 <?php

$query2= "SELECT imgage_path,resized_path FROM gallery WHERE album=?"; 
 $stmt = $connection->prepare($query2);
 $stmt->bind_param("s",$album_names);
 $stmt->execute();
 $result2=$stmt->get_result();
       while ($row2 = $result2->fetch_array(MYSQLI_BOTH)) { //Second while loop


  $thumbnail_path = =htmlspecialchars($row2['resized_path']);
  $image_path =htmlspecialchars($row2['image_path']);

     ?>
          <a href="<?php echo $image_path ?>">
          <img src="<?php echo $thumbnail_path ?>" alt="Illustration" />
                </a>

            </li>
        </ul>
  <?php

   } //Second While loop ends

} //First While loop ends

?>

问题是它只显示$image_path和$thumbnail_path的第一个结果，但我希望它显示属于该特定相册的所有图像路径。

希望我已经解决了我的问题。

Answer 1

这看起来像伪代码（因为它没有正确的php标签）。无论如何，问题如下..你的html标签li安排是错误的。这就是为什么你没有看到其他结果。它必须修复如下

<?php
    $query= "SELECT album_name FROM gallery group by album_name order by MIN(date_time)";
    $stmt = $connection->prepare($query);
    $stmt->execute();
    $result=$stmt->get_result();
    while ($row = $result->fetch_array(MYSQLI_BOTH)) { //First while loop
    $album_names =htmlspecialchars($row['album_name']);` 
?>
<ul>
    <li data-tags="<?php echo $album_names ?>"> 
    <?php

        $query2= "SELECT imgage_path,resized_path FROM gallery WHERE album=?"; 
        $stmt = $connection->prepare($query2);
        $stmt->bind_param("s",$album_names);
        $stmt->execute();
        $result2=$stmt->get_result();
        while ($row2 = $result2->fetch_array(MYSQLI_BOTH)) { //Second while loop


        $thumbnail_path = =htmlspecialchars($row2['resized_path']);
        $image_path =htmlspecialchars($row2['image_path']);

    ?>
    <a href="<?php echo $image_path ?>">
        <img src="<?php echo $thumbnail_path ?>" alt="Illustration" />
    </a>

    <?php
    } //Second While loop ends
    ?>
    </li>
</ul>
<?php

} //First While loop ends

?>

Answer 2

简化为单个查询。这假设image_path和resized path一直都存在于每个图像中（如果它们不容易修复，但这显示了基础）。

<?php

// Query gets one row per album. Row has 3 fields, album name, then all the image_path fields concatentated together, the all the resized_path fields joined together
$query= "SELECT album_name 
                GROUP_CONCAT(image_path ORDER BY image_path) AS image_path_concat,
                GROUP_CONCAT(resized_path ORDER BY image_path) AS resized_path_concat
        FROM gallery 
        GROUP BY album_name 
        ORDER BY MIN(date_time)";
$stmt = $connection->prepare($query);
$stmt->execute();
$result=$stmt->get_result();
// Start of unordered list of album names
echo "<ul>";
while ($row = $result->fetch_array(MYSQLI_BOTH)) 
{ 
    $album_names = htmlspecialchars($row['album_name']); 
    // List item of album name
    echo "<li data-tags='$album_names'>"; 

    // Explode out the image paths into an array
    $image_path = explode(',', $row['image_path_concat']);
    // Explode out the image resized paths into an array
    $resized_path = explode(',', $row['resized_path_concat']);

    // Start of unordered list of image paths
    echo "<ul>";

    // Loop around the array of image paths
    foreach($image_path AS $key=>$value)
    {
        // Assuming that the list of image paths always match the array of resized paths then use the key of the current
        // image_path for both the image path and also the resized / thumbnail path
        $image_path = htmlspecialchars($image_path[$key]);
        $thumbnail_path = htmlspecialchars($resized_path[$key]);

        echo "<li><a href='".$image_path."'><img src='".$thumbnail_path."' alt='Illustration' /></a></li>";
    }
    // End of unordered list of image paths
    echo "</ul>";
    // End of list item of album name
    echo "</li>";

} //First While loop ends

// End of unordered list of album names
echo "</ul>";

?>

Answer 3

我不知道我的回答是否会对你有帮助。

但我认为你的html标签循环有错误。

＆＃13;

 <?php

$query2= "SELECT imgage_path,resized_path FROM gallery WHERE album=?"; 
 $stmt = $connection->prepare($query2);
 $stmt->bind_param("s",$album_names);
 $stmt->execute();
 $result2=$stmt->get_result();
       while ($row2 = $result2->fetch_array(MYSQLI_BOTH)) { //Second while loop


  $thumbnail_path = =htmlspecialchars($row2['resized_path']);
  $image_path =htmlspecialchars($row2['image_path']);

     ?>
          <a href="<?php echo $image_path ?>">
          <img src="<?php echo $thumbnail_path ?>" alt="Illustration" />
                </a>

            </li> <- you loop the close <li> tag
        </ul> <- you loop the close <ul> tag
  <?php

   } //Second While loop ends

} //First While loop ends

?>

＆＃13;

您在第二个循环中循环关闭标记（li和ul），但是您没有为li和ul放置开放标记。我希望这有帮助。三江源

php mysql while循环里面while循环查询同一个表

3 个答案: