Question

我正在尝试使用函数为数字gusser编写代码： playOneGame函数的返回类型应为void。它应该在1到100的范围内实现一个完整的猜谜游戏 shouldPlayAgain函数应该有一个布尔返回类型。它应该提示用户确定用户是否想要再次播放，读入一个字符，如果该字符是'y'则返回true，否则返回false。此外，您应该实现辅助函数getUserResponseToGuess和getMidpoint。应该在playOneGame函数中调用它们。 getUserResponseToGuess。此功能应该提示用户使用短语“是吗？（h / l / c）：“替换令牌的值。它应该返回一个char。 char应该是三个可能值之一：'h'，'l'或'c'。它应该有以下签名： char getUserResponseToGuess（int guess） getMidpoint。这个函数应该接受两个整数，它应该返回两个整数的中点。如果在范围的中间有两个值，那么您应该始终选择两者中较小的一个。它应该有以下签名： int getMidpoint（int low，int high）我从头开始，但我仍然无法得到它的逻辑。这就是我到目前为止所做的。

#include<iostream>
using namespace std;

 void playOneGame;
 char getUserResponseToGuess(int guess);
 int getMidpoint ( int low, int high);

int main() {
do
 {
 playOneGame();
} while (shouldPlayAgain());
return 0;
}
void playOneGame
{
int a = 100;


cout << "\nGuess a number between 1 and 100. " <<endl;
getUserResponseToGuess ( a);

 }


char getUserResponseToGuess(int guess)
{
while (true)
{
int guess = getMidpoint(minimum, maximum);
std::cout << "\nIs it [h]igher/[l]ower/[e]qual to " << guess << "? ";
char answer;
if (!(std::cin >> answer))
{
    std::cerr << "error reading user input, program exiting\n";
    exit(1);
}
if (answer == 'h')
    minimum = guess + 1;
else if (answer == 'l')
    maximum = guess - 1;
else if (answer == 'e')
{
    std::cout << "Well, isn't that nice.\n";
    return;
}
if (minimum > maximum)
{
    std::cerr << "hey, you lied to me!\n";
    exit(1);
}
}
}

int getMidpoint ( int low, int high)
{

int mid;

mid = (low + high) / 2;

return mid;

}

Answer 1

猜测循环应该像这样循环：

while (true)
{
    int guess = getMidpoint(minimum, maximum);
    std::cout << "\nIs it [h]igher/[l]ower/[e]qual to " << guess << "? ";
    char answer;
    if (!(std::cin >> answer))
    {
        std::cerr << "error reading user input, program exiting\n";
        exit(1);
    }
    if (answer == 'h')
        minimum = guess + 1;
    else if (answer == 'l')
        maximum = guess - 1;
    else if (answer == 'e')
    {
        std::cout << "Well, isn't that nice.\n";
        return;
    }
    if (minimum > maximum)
    {
        std::cerr << "hey, you lied to me!\n";
        exit(1);
    }
}

使用函数和中点在c ++中编号Gusser

1 个答案: