Question

我正在从XML文件中解析文本和图像。文字很好。但是当我开始解析图像时，listview变空了。

    for (int j = 0; j < clength; j++) {

                        Node thisNode = nchild.item(j);

                        String theString = null;

                        String nodeName = null;

                        if (thisNode != null && thisNode.getFirstChild() != null) {
                                theString = thisNode.getFirstChild().getNodeValue();                          
                        }

                        nodeName = thisNode.getNodeName();

                        if ("title".equals(nodeName)) {                     
                                _item.setTitle(theString);                          
                            }

                        if ("pubDate".equals(nodeName)) {               
                                String formatedDate = theString.replace(" +0000", "");
                                _item.setDate(formatedDate);
                        }   

                        if (nodeName.equals("enclosure")) {
                               Element enclosure = (Element) thisNode;
                                    if (enclosure.hasAttr("url")) {

                                    String imageLink = (enclosure.attr("url"));
                                        _item.setImage(imageLink);
                                    }
                        }

}

所以，据我所知，问题是从中获取数据。我该如何以正确的方式做到这一点？日Thnx！

Answer 1

所以，我通过这种方式解决了这个问题。

 String body = nodeToString(thisNode);

 int urlStart = body.indexOf("url=");
 int urlFinish = body.indexOf("length");

 String urlImage = body.substring(urlStart+5, urlFinish-2);

 _item.setImage(urlImage);

方法nodeToString：

private String nodeToString(Node node) {
StringWriter sw = new StringWriter();
    try {
            Transformer t = TransformerFactory.newInstance().newTransformer();
            t.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
            t.transform(new DOMSource(node), new StreamResult(sw));
    } catch (TransformerException te) {
        System.out.println("nodeToString Transformer Exception");
    }
      return sw.toString();
}

从XML <enclosure> </enclosure>解析图像

1 个答案: