我正在使用enclosure标记解析xml。我怎样才能做到这一点?我可以轻松地获取链接,guid,title和pubDate标记并将它们解析为NSString,但如果我尝试从enclosure标记创建一个字符串,它将返回null。
我只需要在播客剧集的这一部分中找到的网址:
<enclosure url="http://treymorgan.podbean.com/mf/feed/bf8mvq/Accommoditions.mp3" length="29865594" type="audio/mpeg"/>
答案 0 :(得分:1)
如果您使用的是NSXMLParser,您可以像这样读取url属性(假设您有一个名为podcastURL的属性来存储已解析的URL):
- (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict {
if ([elementName isEqualToString:@"enclosure"]) {
self.podcastURL = [attributeDict objectForKey:@"url"];
}
}
答案 1 :(得分:0)
这是对上述问题的直接回答。我遇到了同样的事情。排序归功于此ATOM data parse with GData post
- (void)parseRss:(GDataXMLElement *)rootElement entries:(NSMutableArray *)entries
{
NSArray *channels = [rootElement elementsForName:@"channel"];
for (GDataXMLElement *channel in channels) {
NSString *blogTitle = [channel valueForChild:@"title"];
NSArray *items = [channel elementsForName:@"item"];
for (GDataXMLElement *item in items) {
NSString *podcastEnclosureUrl = nil;
NSString *articleTitle = [item valueForChild:@"title"];
NSArray *enclosureArray = [item elementsForName:@"enclosure"]; //this is the code for what I needed
for (GDataXMLElement *content in enclosureArray)
{
NSString *podcastEnclosureUrl = [[content attributeForName:@"url"] stringValue];
NSLog(@"URL: %@", podcastEnclosureUrl);
}
NSString *articleDateString = [item valueForChild:@"pubDate"];
NSDate *articleDate = [NSDate dateFromInternetDateTimeString:articleDateString formatHint:DateFormatHintRFC822];
RSSPodcastFeed *entry = [[RSSPodcastFeed alloc] initWithBlogTitle:blogTitle
articleTitle:articleTitle
podcastEnclosureUrl:podcastEnclosureUrl
articleDate:articleDate];
[entries addObject:entry];
}
}
}