背包动态编程输入

时间:2014-09-06 22:48:13

标签: java dynamic-programming memoization knapsack-problem

我想知道是否有任何针对背包问题的具体问题和答案,我可以输入并修改此代码,以确保我做得正确?我试图进入动态编程并开始解决这个问题,但是没有办法知道它是否在没有输入的情况下工作 - 我在一些功率点上发现了一些情况,而我的代码输出了正确的信息,是非常基本和简单的案例,所以我想确保这更加丰富的输入。

这是我的代码:

import java.util.ArrayList;

public class Knapsack {

    private int numThings = 0;

    public static void main(String[] args) {

        (new Knapsack()).run();
    }

    public void run() {

        ArrayList<Thing> thingList = new ArrayList<Thing>();
        thingList.add(new Thing(60, 2));
        thingList.add(new Thing(75, 3));
        thingList.add(new Thing(90, 4));


        int maxWeight = 5;


        int[] vals = new int[maxWeight + 1];
        vals[2] = 60;

        Thing nullThing = new Thing(0,0);
        Thing max;
        int maxSet = 0;

        for (int i = 1; i < vals.length; i++) {// lets go through weights leading up to our maximal weight

            System.out.println(i);
            max = nullThing;
            for (Thing x : thingList) {

                if ((i-x.getWeight() >= 0) && (x.getValue() + vals[i-x.getWeight()] > max.getValue() + vals[i-max.getWeight()])) {

                    max = x;
                    maxSet = 1;//here, we compare possibilities of adding items by subtracting weights from  our current index and seeing which ones produce the highest values
                }
            }

            if (maxSet == 1) {

                vals[i] = max.getValue() + vals[i-max.getWeight()];
                System.out.println(max.info() );//if we find something that sets a highest value, we cache that info into the array for future use
            }
        }

        System.out.println(vals[maxWeight]);


    }


    private class Thing {

        private int value, weight;

        public Thing(int v, int w) {

            value = v;
            weight = w;

        }

        public int getValue() {

            return value;
        }

        public int getWeight() {

            return weight;
        }

        public String info() {

            return "I have a weight of "+weight+" and a value of "+ value;
        }
    }
}

1 个答案:

答案 0 :(得分:0)

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