JPA，继承JOINED，多个ID

Question

我有一点JPA问题。 假设你有这样的表:(结构是固定的）

PERSON
--
ID, 
DEPARTMENT_ID 

...

SPECIALWORKER
------
ID, PERSON_ID, SPECIALDEPARTMENT_ID

...

DEPARTMENT
-------
ID, 

...

SPECIALDEPARTMENT
-------
ID, 

...

在Java中，我将使用简单的层次结构构建它：SpecialWorker extends Person和SpecialDepartment extends Department。我们将拥有简单的＆＃34;人和简单＆＃34;部门。

在JPA中，我尝试使用JOINED_Table继承构建该场景，但我无法使其正常工作。有什么想法吗？

修改的

编码，我希望我什么都不会错过。 当我尝试插入一个特殊工作者时，我得到了完整性异常。 当我插入一个特殊工作者时，jpa必须将fk设置为离开（基类人）以及将fk设置为特殊部分（来自具体当前类）

 @Entity
  @Table(name = "DEPARTEMENT")
  @Access(AccessType.FIELD)
  @Inheritance(strategy = InheritanceType.JOINED)
  public class Departement
  {
        @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "ID")
    private Integer id;

    ...
  }

  @Entity
  @Table(name = "SPECIALDEPARTEMENT")
  @Access(AccessType.FIELD)
  @PrimaryKeyJoinColumn(name = "ID_DEPARTEMENT", referencedColumnName = "ID")
  public class SpecialDepartement
    extends Departement
    implements Serializable
  {


    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "ID", updatable = false, insertable = false)
    private Integer                                                 id01;

    @OneToMany(mappedBy = "specialDepartement", cascade = CascadeType.ALL, orphanRemoval = true)
    private List<SpecialWorker> workers;

    ...

  }



  @Entity
  @Table(name = "PERSON")
  @Access(AccessType.FIELD)
  @Inheritance(strategy = InheritanceType.JOINED)
  public class Person
  {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "ID")
    @Max(19)
    private Long                        id;

    @ManyToOne
    @JoinColumn(name = "ID_DEPARTEMENT", referencedColumnName = "ID", nullable = false)
    private Departement departement;

    ...
  }



  @Entity
  @Table(name = "SWORKER")
  @Access(AccessType.FIELD)
  @PrimaryKeyJoinColumn(name = "ID_PERSON", referencedColumnName = "ID")
  public class SpecialWorker
    extends Person
  {

    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "ID", updatable = false, insertable = false)
    private Integer                     id01;

    @ManyToOne
    @JoinColumn(name = "ID_SPECIALDEPARTEMENT", referencedColumnName = "ID", nullable = false)
    private SpecialDepartement  specialdepartement;