我有一个UDF,它根据进入表格的一系列值计算得分。
在表创建过程中必须应用/调用UDF,这是我遇到一点麻烦的地方。
UDF必须使用仅使用方法的情况创建,因此我无法对此进行更改,但我确信我只是稍微有点了。
我不确定答案是否已经存在,但是我还没有发现它,但是如果这已经得到了解答,那么就道歉了。
这是首先创建的UDF
--Create UDF
create function [dbo].[cupidscoreUDF]
(
@gender char(1),
@name varchar(15),
@dob datetime,
@weight int,
@height int,
@smoker bit,
@salary int
)
returns int
as
begin
declare @score int
-- To determine age in years
declare @Age int
select @Age = DATEDIFF(YEAR, @dob, GETDATE())
select
@score = case
when @Age between 20 and 30 then 5
when @Age between 31 and 40 then 4
when @Age between 41 and 50 then 3
when @Age > 50 then 2
else 0
end
-- To determine the height/weight ratio
declare @WeightHeight int
set @WeightHeight = @weight / @height
set
@score = @score +
case
when @WeightHeight between 20 and 25 then 1
when @WeightHeight between 25 and 30 then 3
when @WeightHeight between 30 and 35 then 4
when @WeightHeight between 35 and 40 then 2
else 0
end
-- If non-smoker add 2 points
if @smoker = 0
set @Score = @Score + 2
-- To determine score by salary
set
@score = @score +
case
when @salary < 50000 then 1
when @salary between 500001 and 60000 then 2
when @salary between 60001 and 70000 then 3
when @salary > 70000 then 4
end
return @score
end
;
现在,我在桌面创建过程中获得了
-- Create Member_Profile table
create table Member_Profile
(
MemberID int primary key,
Gender varchar(6),
Name varchar(50),
Dob datetime,
Weight int,
Height int,
Smoker bit,
Salary int,
Cupid as dbo.cupidscoreUDF
)
GO
insert into Member_Profile (Gender, Name, Dob, Weight, Height, Smoker, Salary) values ('Male','James',19931115, 75, 180, 0, 80000);
insert into Member_Profile (Gender, Name, Dob, Weight, Height, Smoker, Salary) values ('Female','Rosie',19870912, 45, 150, 0, 100000);
insert into Member_Profile (Gender, Name, Dob, Weight, Height, Smoker, Salary) values ('Male','Richard',19630402, 95, 168, 1, 200000);
select * from Member_Profile
UDF获取会员的信息,然后计算他们的丘比特&#39;从中得分,然后将其与其他所有内容一起插入到表格中。
使用UDF的任何帮助都很棒
答案 0 :(得分:1)
尝试将此用于丘比特专栏:
Cupid as dbo.cupidscoreUDF(Gender, Name, Dob, Weight, Height, Smoker, Salary)
答案 1 :(得分:1)
我非常认真地建议将UDF的调用移到insert / update而不是表定义。为了使这更容易,您可以创建一个简单的插入/更新过程来调用UDF。这样你就可以避免两次提供数据。
这是一个非常通用的例子,在这个例子中,为一些如此简单的事情做所有额外步骤看起来有点奇怪,但是当你应用实际场景时会很快改变。
use demo
go
create table dbo.example_table (
id int identity(1,1) primary key,
some_value_1 int,
some_value_2 int,
some_calculation int)
go
create function dbo.calculator_function (
@value1 int,
@value2 int)
returns int
as
begin
declare @result int = (select @value1 + @value2 as result)
return @result
end
go
create procedure dbo.insert_example
@value1 int,
@value2 int
as
insert dbo.example_table (some_value_1,some_value_2,some_calculation)
select @value1, @value2, dbo.calculator_function(@value1,@value2)
go
exec dbo.insert_example 1,2
go
select * from example_table
答案 2 :(得分:0)
我假设你在VUW,我假设你像我一样做着341。 使用触发器调用UDF - 我已经给你足够的开始,你需要声明并设置你认为必要的变量才能工作
CREATE TRIGGER [dbo].[CalculateCupid]
ON [dbo].[Member_Profile]
AFTER INSERT
AS
BEGIN
UPDATE DBO.Member_Profile
SET Cupid_Score = @Cupid_Score WHERE MemberID=@MemberID
END