我有一个代码,当我有小的CSV数据时工作正常,但当我尝试通过它运行大型CSV时出错。实质上,这段代码应该将3个CSV值的数据放入3个单独的词典中,将这些词典组合成主词典,然后在字典上执行算术运算。输入的CSV看起来像这样:
time A B C D
0 3 4 6 4
.001 4 6 7 8
.002 4 6 7 3
我使用的代码是下面显示的代码。错误发生在第47和第65行,我试图用字典预先形成算术。关于为什么会这样做的任何解释都非常感谢。
import numpy
Xcoord = {}
time = []
with open ('Nodal_QuardnetsX2.csv', 'r') as f:
f.readline() # Skips first line
for line in f:
values = [s.strip()for s in line.split(',')]
Xcoord[values[0]] = map(float, values[1:])
time.append(values[0])
Ycoord = {}
with open ('Nodal_QuardnetsY2.csv', 'r') as f:
f.readline() # Skips first line
for line in f:
values = [s.strip()for s in line.split(',')]
Ycoord[values[0]] = map(float, values[1:])
Zcoord = {}
with open ('Nodal_QuardnetsZ2.csv', 'r') as f:
f.readline() # Skips first line
for line in f:
values = [s.strip()for s in line.split(',')]
Zcoord[values[0]] = map(float, values[1:])
# Create a master dictionary of the form {'key':[[x, y, z], [x, y, z]}
CoordCombo = {}
for key in Xcoord.keys():
CoordnateList = zip(Xcoord[key], Ycoord[key], Zcoord[key])
CoordCombo[key] = CoordnateList
counter = 0
keycount1 = 0
keycount2 = 0.001
difference = []
NodalDisplacements = {}
#Find the difference between the x, y, and z quardnets relative to that point in time
while keycount2 <= float(values[0]):
Sub = numpy.subtract(CoordCombo[str(keycount2)][counter], CoordCombo[str(keycount1)][counter])
counter = counter + 1
difference.append(Sub)
NodalDisplacements[keycount1] = Sub
keycount1 = keycount1 + 0.001
keycount2 = keycount2 + 0.001
counter = 0
keycount3 = 0
keycount4 = 0.001
Sum = []
breakpoint = float(values[0])-0.001
while keycount4 <= breakpoint:
Add = numpy.sum(NodalDisplacements[keycount4][counter], NodalDisplacements[keycount3][counter])
Sum.append(Add)
keycount3 = keycount3 + 0.001
keycount4 = keycount4 + 0.001
counter = counter + 1
if counter == 2:
counter = 0
print Sum
答案 0 :(得分:0)
你的csv文件的一行可能不包含5个元素,或者该行为空。 在你的逻辑中,我建议使用
for line in f:
line = line.strip()
if not line: continue
if len(values) != N_COLS: continue # or error...
# other ...