Question

我目前正在编写一个程序，将便士转换为正确数量的二十，数十，五，美元，四分之一，硬币，镍币和便士。我已经得到了程序的第一部分正确但是一旦我得到美元，我的数学输出的数据并不正确。有什么帮助吗？

import java.util.Scanner;

public class assignment1 {

public static void main(String[] args) {
    Scanner inputReader = new Scanner(System.in);

    int num, remainder;

    System.out.print("Enter a value as a number of pennies: ");
    num = inputReader.nextInt();

    remainder = num % 2000;

    System.out.println(num + " pennies is equal to:");
    System.out.println((num / 2000) + " twenties");
    System.out.println((remainder / 1000) + " tens");
    System.out.println(((remainder % 1000) / 500) + " fives");
    System.out.println((((remainder % 1000) % 500) / 100) + " dollars");
    System.out.println(((((remainder % 1000) % 500) % 100) / 25) + " quarters");
    System.out.println(((((remainder % 1000) % 500) % 100) % 25) / 10 + " dimes");
    System.out.println((((((remainder % 1000) % 500) % 100) % 25) % 10) / 5 + " nickels");
    System.out.println(((((((remainder % 1000) % 500) % 100) % 25) % 10) % 5) / 1 + " pennies");

}
}

Answer 1

只有数学运算符才有可能。在您遇到的大多数其他编程任务中，您应该使用控制结构来完成算法中的步骤。

<强>过程

从便士的数量开始，
除以2000（20美元的价值）并分配给新变量
减去二十几岁时的便士数，
重复后续面额（10美元账单，5美元账单等）

Answer 2

确定。我明白你做了什么。让我们从

开始

System.out.println((num / 2000) + "twenties");
System.out.println((remainder / 1000) + "tens");
System.out.println((remainder / 1000) % 500 + "fives");
System.out.println((((remainder / 1000) % 500) % 100) + "dollars");

第一行是正确的。但是你不能使用简单的余数来保持运行记录。此外，num和remainder是可怕的变量名称。对于正在运行的计数，你可以做这样的事情，

System.out.print("Enter a value as a number of pennies: ");
int pennies = inputReader.nextInt();
System.out.println(pennies + " pennies is equal to:");
int twenties = pennies / 2000;
pennies -= twenties * 2000;
int tens = pennies / 1000;
pennies -= tens * 1000;
int fives = pennies / 500;
pennies -= fives * 500;
int dollars = pennies / 100;
pennies -= dollars * 100;
int quarters = pennies / 25;
pennies -= quarters * 25;
int dimes = pennies / 10;
pennies -= dimes * 10;
int nickels = pennies / 5;
pennies -= nickels * 5;
System.out.printf("%d twenties, %d tens, %d fives, %d dollars, "
        + "%d quarters, %d dimes, %d nickels, %d pennies%n", twenties,
        tens, fives, dollars, quarters, dimes, nickels, pennies);

那将输出（以5869作为输入），

5869 pennies is equal to:
2 twenties, 1 tens, 1 fives, 3 dollars, 2 quarters, 1 dimes, 1 nickels, 4 pennies

或者（如果你想要一个非运行的计数器），只需从便士中删除减法，如

System.out.println(pennies + " pennies is equal to:");
int twenties = pennies / 2000;
int tens = pennies / 1000;
int fives = pennies / 500;
int dollars = pennies / 100;
int quarters = pennies / 25;
int dimes = pennies / 10;
int nickels = pennies / 5;
System.out.printf("%d twenties, %d tens, %d fives, %d dollars, "
        + "%d quarters, %d dimes, %d nickels, %d pennies%n", twenties,
        tens, fives, dollars, quarters, dimes, nickels, pennies);

对于5869，你得到

5869 pennies is equal to:
2 twenties, 5 tens, 11 fives, 58 dollars, 234 quarters, 586 dimes, 1173 nickels, 5869 pennies

Answer 3

我认为问题在于，每次分割数字时，它都会返回一个新数字作为整数。因此，如果你将100便士除以1000就会返回0，所以无论你做什么，你的数学剩余部分都会返回0。

基于您的代码的示例：

//assuming the input is 100 pennies the first remainder/1000 will equal to 0
System.out.println(((((((remainder / 1000) % 500) % 100) % 25) % 10) %5) % 1 + "pennies");

你还没有指定你必须使用模数，所以我假设你没有。这就是我要做的事情：

System.out.println(num + " pennies is equal to:");
System.out.println((num / 2000) + "twenties");
System.out.println((num / 1000) + "tens");
System.out.println((num / 500) + "fives");
System.out.println((num / 100)  + "dollars");
System.out.println((num / 25)  + "quarters");
System.out.println((num / 10) + "dimes");
System.out.println((num / 5) + "nickels");
System.out.println(num   + "pennies");

硬币数学转换问题

3 个答案: